Given expression is x² - 121
This is called Difference of Squared terms, we have a formula that is given as :-
a² - b² = (a - b) · (a + b)
Now using the above formula in the given expression, we get :-
x² - 121
x² - (11)²
here a = x and b = 11
x² - (11)² = (x - 11) · (x + 11)
but it says that student gave the answer as (x - 11) · (x - 11).
So, student's answer should be (x - 11) · (x + 11) instead of product of two (x - 11) terms.
Answer:
B=![\left[\begin{array}{ccc}0&0\\0&1\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%260%5C%5C0%261%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Let's do the multiplication AB.
If A=![\left[\begin{array}{ccc}1&0\\0&0\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%260%5C%5C%5Cend%7Barray%7D%5Cright%5D)
then the first row of A is= (1 0) by the first column of B= (0 0) is equal to zero.
the first row of A is= (1 0) by the second column of B= (0 1) is equal to zero too because 1.0+0.1=0.
the second row of A is= (0 0) by any colum of B is equal to zero too.
So we have found an example that works!
The answer is $50
Assume the original cost price to be $x
Therefore ,
X - 36X/100 = $32
-> 100x - 36x = 32 x 100
-> 64x = 3200
-> x = 3200/64
-> x = 50