Since we are already given the amount of jumps from the first trial, and how much it should be increased by on each succeeding trial, we can already solve for the amount of jumps from the first through tenth trials. Starting from 5 and adding 3 each time, we get: 5 8 (11) 14 17 20 23 26 29 32, with 11 being the third trial.
Having been provided 2 different sigma notations, which I assume are choices to the question, we can substitute the initial value to see if it does match the result of the 3rd trial which we obtained by manual adding.
Let us try it below:
Sigma notation 1:
10
<span> Σ (2i + 3)
</span>i = 3
@ i = 3
2(3) + 3
12
The first sigma notation does not have the same result, so we move on to the next.
10
<span> Σ (3i + 2)
</span><span>i = 3
</span>
When i = 3; <span>3(3) + 2 = 11. (OK)
</span>
Since the 3rd trial is a match, we test it with the other values for the 4th through 10th trials.
When i = 4; <span>3(4) + 2 = 14. (OK)
</span>When i = 5; <span>3(5) + 2 = 17. (OK)
</span>When i = 6; <span>3(6) + 2 = 20. (OK)
</span>When i = 7; 3(7) + 2 = 23. (OK)
When i = 8; <span>3(8) + 2 = 26. (OK)
</span>When i = 9; <span>3(9) + 2 = 29. (OK)
</span>When i = 10; <span>3(10) + 2 = 32. (OK)
Adding the results from her 3rd through 10th trials: </span><span>11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 = 172.
</span>
Therefore, the total jumps she had made from her third to tenth trips is 172.
Answer:
City 2 has a higher temperature
Step-by-step explanation:
Given
Required
Convert 34°C to °F
Substitute 34 for C in the above formula:
<em>Comparing 93.2 to City 2's temperature of 97; we can conclude that city 2 has a higher temperature</em>
Alright
for a 45-45-90 triangle, if the legs are x then the hytponuse is x√2
so LM=x√2 is right
NM=x
also, tan=oposite side/adjacent side
so that would be LN/MN or MN/LN=x/x=1
so that would be tan(45)=1
so you want to check the 1st one, 3rd one and 5th one
NM=x
LM=x√2
tan(45°)=1 are the answers
Answer:
An isohyet is a line on a map which connects points that have the same amounts of precipitation in a given period or for a particular storm.
Step-by-step explanation:
