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HACTEHA [7]
3 years ago
13

Use the elimination method to solve the following system of equations.

Mathematics
1 answer:
aliya0001 [1]3 years ago
3 0
The answer 
<span>2x - y + z = -3          (1)
2x + 2y + 3z = 2       (2)
3x - 3y - z = -4          (3)

</span> (1) - (2)              3y +2z =5
 3 .(1) - 2.(2)       3y+5z = -1<span>

let 's solve 
</span>3y +2z =5
3y+5z = -1<span>
z= - 2, and 3y =5+4=9,  y=3, so  </span>2x - 3 -2 = -3 implies x= 1
<span>
finally x=1, y=3 and z= -2
proof 
</span>2x - y + z = -3??     2.1 - 3 -2 = -3  (true)<span>

</span>
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Quadrilateral ABCD is dilated by a scale factor of 1 over 3 centered around (1, 2). Which statement is true about the dilation?
Sonbull [250]

<em>Note: Since you missed to add the figure. So, after a little research I am kind of able to find the figure and hence, assuming it as a reference. Hence, I am attaching the figure and solution of that figure is also visible in the same figure.</em> Please check the attached figure (a)

Answer:

Segment B'D' will be parallel to segment BD and will be shorter than segment BD. Please see the attached figure (a) for better understanding.

Step-by-step explanation:

As we know that there are certain rules when a quadrilateral is dilated by a certain scale centered around a certain point.

So,

Let suppose P(a, b) is the point.

The dilation rule by a scale factor of 1 over 3 or (1/3) centered around (1, 2) is

P(a, b) → P(\frac{x+2}{3}, \frac{y+4}{3})

Hence,

            A(1, 2) → A'(1, 2)

            B(2, 3) → B'(4/3, 7/3)

            C(4, 2) → C'(2, 2)

             D(2, 1) → D'(4/3, 5/3)

The attached figure show that if we draw the all these points in the coordinate plan i.e. A(1, 2), B(2, 3), C(4, 2), D(2, 1) and A'(1, 2), B'(4/3, 7/3), C'(2, 2), D'(4/3, 5/3), we can determine that Segment B'D' will be parallel to segment BD and will be shorter than segment BD.

<em>Keywords: dilation, quadrilateral, segment</em>

<em> Learn more about dilation from brainly.com/question/7569824</em>

<em> #learnwithBrainly</em>

7 0
3 years ago
Find the area of the shape below.
Otrada [13]

Area  = 10.08 yd²

Solution:

The given shape is a trapezoid.

Length of top base (b_1) = 5.4 yd

Length of bottom base (b_2) = 1.8 yd

Height of trapezoid (h) = 2.8 yd

<u>To find the area of the trapezoid:</u>

Area of the trapezoid = \frac{1}{2}\times (b_1+b_2)\times h

                                    $=\frac{1}{2}\times (5.4+1.8)\times 2.8

                                    $=\frac{1}{2}\times 7.2\times 2.8

                                    = 10.08 yd²

Area  = 10.08 yd²

3 0
3 years ago
D=24 ft<br> Find the radius
laila [671]
Radius is always gonna be half of what the diameter is
8 0
2 years ago
Read 2 more answers
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creativ13 [48]

(–13 – 5) – (8 + 2)

= - 18 - 10

= -28

Answer

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3 years ago
Find the slope of the two points: 2 -4, 6,-7
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Answer:

-3/4 or -0.75

Step-by-step explanation:

-7- (4)= -3

6-2=4

-3/4

(use y2-y1/x2-x1)

6 0
3 years ago
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