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gladu [14]
3 years ago
12

*ANSWER PLS TYY* Which of the following statements is TRUE about finding the area of a polygon? a.) You can use a coordinate pla

ne to find the area of a polygon only if it is a triangle, rectangle, or square. b.) You can find the area of a polygon by dividing it into triangle and rectangle sub-parts, finding the area of the sub-parts, and then calculating the sum of the areas. c.) You can find the area of a polygon by dividing it into triangle and rectangle sub-parts and then calculating the area for only one of those sub-parts. d.) You can only find the area of a polygon if it is a triangle, rectangle, or square.
Mathematics
2 answers:
ruslelena [56]3 years ago
3 0

Answer:

The answer to this question is b)

Gala2k [10]3 years ago
3 0
The answer would be B
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Chloe drew a triangle with side lengths of 30 centimeters, 24 centimeters, and 18 centimeters. Juan drew a triangle with side le
vlada-n [284]

Answer:

A and B

Step-by-step explanation:

Each side in Chloe's triangle is 1.5 times the length of each side in Juan's triangle.  Thus, they are 'similar' by the <u>math </u>definition of that word, by the SSS Rule for Similar Triangles.

That means they are different only in size. So, their angle measures are the same and they are the same shape.

A and B are true.

C is never true, because the sum of all 3 angles in a triangle is always 180°.

D is not true, because they are similar.

5 0
3 years ago
X+y=4 and x-y=6 substitution
vlabodo [156]
Y = -1
x = 5
jeng jeng jeng
4 0
3 years ago
Read 2 more answers
What is the value of x in the equation 4(2x + 10) = 0? (1 point)
miskamm [114]

Answer:

x = -5

Explanation:

4(2x + 10) = 0

[ Simplify both sides of the equation ]

4(2x + 10) = 0

(4)(2x) + (4)(10) = 0 [Distribute]

8x + 40 = 0

[ Subtract 40 from both sides ]

8x + 40 − 40 = 0 − 40

8x = −40

[ Divide both sides by 8 ]

8x  / 8 = −40 / 8

x = -5

4 0
3 years ago
Write the equation of a hyperbola with vertices (0, -4) and (0, 4) and foci (0, -5) and (0, 5).
andre [41]
Check the picture below.  So, more or less looks like so.

notice, the center is clearly at the origin, and notice how long the "a" component is, also, bear in mind that, is opening towards the y-axis, that means the fraction with the "y" variable is the positive one.

Also notice, the "c" distance from the center to either foci, is just 5 units.

\bf \textit{hyperbolas, vertical traverse axis }\\\\&#10;\cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1&#10;\qquad &#10;\begin{cases}&#10;center\ ({{ h}},{{ k}})\\&#10;vertices\ ({{ h}}, {{ k}}\pm a)\\&#10;c=\textit{distance from}\\&#10;\qquad \textit{center to foci}\\&#10;\qquad \sqrt{{{ a }}^2+{{ b }}^2}&#10;\end{cases}\\\\&#10;-------------------------------\\\\

\bf \begin{cases}&#10;h=0\\&#10;k=0\\&#10;a=4\\&#10;c=5&#10;\end{cases}\implies \cfrac{(y-{{ 0}})^2}{{{ 4}}^2}-\cfrac{(x-{{ 0}})^2}{{{ b}}^2}=1\implies \cfrac{y^2}{16}-\cfrac{x^2}{b^2}=1&#10;\\\\\\&#10;c=\sqrt{a^2+b^2}\implies c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b&#10;\\\\\\&#10;\sqrt{5^2-4^2}=b\implies \boxed{3=b}&#10;\\\\\\&#10;\cfrac{y^2}{16}-\cfrac{x^2}{3^2}=1\implies \boxed{\cfrac{y^2}{16}-\cfrac{x^2}{9}=1}

7 0
3 years ago
Elizabeth and Markus are playing catch. Elizabeth throws the ball first. The height of the ball can be modeled by the equation h
astra-53 [7]

Answer:

h=-5(16t-144t-7)

Step-by-step explanation:

5 0
3 years ago
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