Alright so I'm coming up with this on the fly; you have the first six letters (a,b,c,d,e,f) and 0-9 and your ten numbers. calculate the amount of possible combinations for the letters by simply writing them down.
ab, ac, ad, ae, a f- five
bc, bd , be, bf- four
cd, ce, cf- three
de, df- two
ef,- one.
adding these all together gets a total of 15 for the letters. now the numbers
01, 02, 03, 04, 05, 06, 07, 08, 09- nine
12, 13, 14, 15, 16, 17, 18, 19- eight
23, 24, 25, 26, 27, 28, 29- seven
34, 35, 36, 37, 38, 39- six
45, 46, 47, 48, 49- five
56, 57, 58, 59- four
67, 68, 69- three
78, 79- two
89- one
added together with a total of 45 combinations.
alright so, 45 different number combinations and 15 letter combinations. multiplying 15 by 45 should tell you the total possible combinations for a two letter and two number serial-number
Considering that the square root of 49 is 7, and 52 > 49, Alejandro was not correct, as the correct integer is of 48.
<h3>What is the integer that has the square root closest to n, without going over?</h3>
The integer that has square root n is given by:
S(n) = n².
Hence the closest is given by:
C(n) = n² - 1.
In this problem, we have n = 7, hence:
C(7) = 7² - 1 = 48.
Which means that Alejandro was not correct.
More can be learned about square roots at brainly.com/question/27678604
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True multiply both sides by 15
Okay. 60 equals twice the number added to itself. That would be 30, because 60 is twice of 30 and 30 added to itself is 60. The number is 30.
