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galina1969 [7]
2 years ago
14

The deep body temperature of a healthy person is 37°C. What is it in kelvins?

Mathematics
1 answer:
Damm [24]2 years ago
7 0

Answer:

The deep body temperature of a healthy person is 310.15 K

Step-by-step explanation:

The formula we are going to use is T_{K}=T_{C}+273.15

We know that the deep body temperature is 37°C, putting this value into the formula we have that T_{K}=37+273.15 = 310.15 K

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Use the discriminant to determine the number of solutions and types of solutions for the quadratic equation, below. Then answer
Setler79 [48]

Answer:

A. Discriminant = 116

B. Number of solutions for the quadratic equation = 2

C. Type of solutions (circle one):Imaginary

D. Type of solutions (circle one):irrational

Step-by-step explanation:

The given quadratic equation is

{x}^{2}  + 8x = 13

We rewrite in standard form to get;

{x}^{2}  + 8x   - 13 = 0

The discriminant is

D =  {b}^{2}  - 4ac

where a=1, b=8, c=-13

We substitute to get:

D =  {8}^{2}  - 4 \times 1 \times  - 13

D = 64  + 52

D = 116

Since the discriminant is great than zero, we have two distinct real roots

6 0
3 years ago
Write the augmented matrix for each system of equations.
Fudgin [204]

<u>We are given the equations: </u>

10x = 10

-5x - 8y = 9

Since we don't have a coefficient of y in the first equation, we will rewrite the first equation as:

10x + 0y = 10

<u>Writing an Augmented matrix for the 2 equations:</u>

10x + 0y = 10

-5x - 8y = 9

\left[\begin{array}{ccc}10&0|&10\\-5&-8|&9\end{array}\right]

5 0
3 years ago
Triangle EFG has coordinates E (-4,4), F (-4,-2), and G (2,-2). Triangle JKL will be a dilation of triangle EFG with a scale fac
denis-greek [22]

The point L is plotted at A. (1, -1).

Step-by-step explanation:

Step 1:

First, we plot the coordinates of both triangles.

The coordinates of the triangle EFG are as follows;

E = (-4, 4), F = (-4, -2), and G = (2, -2).

The coordinates of triangle JKL are;

J = (-2, 2), K = (-2, -1), and L = (x, y).

Step 2;

Next, we need to find the distances between at least two coordinates for both triangles.

The distances between vertical lines are found by calculating the difference in y values while for horizontal lines, the distances are found by calculating the difference between the x values.

The distance of EF = 4-(-2) =6.

The distance of JK = 2-(-1)= 3.

The distance of FG =2-(-4)= 6.

The distance of KL =  (Scale factor)(the distance of FG),

The distance of KL= (\frac{1}{2} )(6) = 3.

Step 3;

So the point L is 3 points away from point k on the x axis.

(x, y) = (-2+3, 1) = (1, -1).

So point L is plotted at option A. (1, -1).

8 0
3 years ago
John's car gets 25.3 miles per gallon. How many<br> miles can he drive on 11.7 gallons of gas?
bekas [8.4K]

Answer:

Multiply 25.3 by 11.7, to get the answer of 296.01

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2 years ago
Real word problems that have more than one answer can be described by relations?
AleksandrR [38]
Yes that is correct!
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