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PolarNik [594]
3 years ago
5

51 correct 9 incorrect write in simplest form

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
5 0
Yesrrrdrrffffffrrrrrdfddddddddf
abruzzese [7]3 years ago
4 0
U have 51 : 9
so you have to find a number that they both divide into
i got that 3 divided into both 51 and 9 so final answer is = 17 : 3
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a rectangular sheet is 62cm long and 42cm wide from each of its corners a square of side 6cm is cut out and an open box is made
Alla [95]

Answer:

The volume of rectangular box is 9,000 cubic centimeters

Step-by-step explanation:

Given as :

The length of the rectangular sheet = L = 62 cm

The width of the rectangular sheet = B = 42 cm

Let The volume of rectangular box = v cubic centimeters

From each corner of sheet a square of 6 cm is cut out and an open box made

So, The length of box = L' = (L - 6 - 6)

i.e L' = (62 - 6 - 6)

Or, L' = 50 cm

Or, Length of the box = 50 cm

And The width of the box = B' = (B - 6 - 6)

i.e B' = (42 - 6 - 6)

Or, B' = 30 cm

Or width of the box = 30 cm

And,

The height of the box = H = 6 cm

∴ volume of rectangular box = Length of box × Breadth of box × Height of  box

i.e v = L' × B' × H

Or, v = 50 cm × 30 cm × 6 cm

Or, v = 9,000 cm³

So, The volume of rectangular box = v = 9,000 cm³

Hence, The volume of rectangular box is 9,000 cubic centimeters Answer

4 0
3 years ago
What value of x makes the equation 0.75(x+20)=2+0.5(x−2) true?
aev [14]

Answer:

x= -56..................

7 0
3 years ago
A square has an area of 561.69m2. Work out the perimeter of the square.
lara [203]

Answer:

The answer is 94.8 m

Step-by-step explanation:

Area of a square is a²

So, 23.7² = 561.69 m²

The side of the square is equal to 23.7 m

Perimeter of a square is the side multiplied by 4

So we have that 23.7 x 4 = 94.8 m

4 0
3 years ago
(1 + 7)^2 +2 simplify
Anon25 [30]

Answer:

66

Step-by-step explanation:

4 0
3 years ago
There are 60 students and 13 teachers on a bus what is the ratio of students to teachers
mixer [17]

60 : 13

30 : 6.5

15 : 3.25

6 0
3 years ago
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