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PolarNik [594]
3 years ago
5

51 correct 9 incorrect write in simplest form

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
5 0
Yesrrrdrrffffffrrrrrdfddddddddf
abruzzese [7]3 years ago
4 0
U have 51 : 9
so you have to find a number that they both divide into
i got that 3 divided into both 51 and 9 so final answer is = 17 : 3
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Using (x + a) (x + b) = x² + (a + b) x + ab, evaluate 75 x 77
Gre4nikov [31]

(x + a) (x + b) = x² + (a + b) x + ab

75 * 77=

=(70+5)(70+7)

=70²+(5+7)*70+5*7

=4900+12*70+35

=4900+840+35

=5775

4 0
3 years ago
to the nearest ten thousand, the population of Vermont was estimated to be about 620,000 in 2008.What might have been the exact
sp2606 [1]
There Are Multiple Answers.... Here are 5 possible answers

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6 0
3 years ago
Which expression is equivalent to 3√32x^8y^10?
denpristay [2]
<span>
3√(32x^8y^10)
= </span><span>3√(16*2 x^8y^10)
= 12x^4y^5 </span>√2

Hope it helps
6 0
4 years ago
Read 2 more answers
If SU and VX are parallel lines and mUTW = 131°, what is mVWT?
TiliK225 [7]

<u>Answer:</u>

∠VWT = 131°

<u>Explanation:</u>

∠VWT is equal to ∠UTW because they are Alternate inner angles. Since they are equal, we know that the measure of ∠VWT is 131°.

Hoped this helped!

4 0
3 years ago
A real estate agent wants to know how many owners of homes worth over​ $1,000,000 might be considering putting their home on the
JulsSmile [24]

Answer:

NO

Step-by-step explanation:

The changeability of a sampling distribution is measured by its variance or its standard deviation. The changeability of a sampling distribution depends on three factors:

  1. N: The number of observations in the population.
  2. n: The number of observations in the sample.
  3. The way that the random sample is chosen.

We know the following about the sampling distribution of the mean. The mean of the sampling distribution (μ_x) is equal to the mean of the population (μ). And the standard error of the sampling distribution (σ_x) is determined by the standard deviation of the population (σ), the population size (N), and the sample size (n). That is

μ_x=p

σ_x== [ σ / sqrt(n) ] * sqrt[ (N - n ) / (N - 1) ]

In the standard error formula, the factor sqrt[ (N - n ) / (N - 1) ] is called the finite population correction. When the population size is very large relative to the sample size, the finite population correction is approximately equal to one; and the standard error formula can be approximated by:

σ_x = σ / sqrt(n).

6 0
3 years ago
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