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iVinArrow [24]
3 years ago
11

Please help me with this

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
6 0

Answer:

$62.50

Step-by-step explanation: 250 divided by 4 equals $62.10

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A beach ball has a diameter of 10 inches. What is the volume of air contained inside the beach ball? Use 3.14 for pi. Round your
Nikitich [7]
A beach ball is a sphere, so we will need to know how to find the volume of a sphere.
V=4π(r³/3)
We have the diameter, but not the radius. To find the radius, it is half of the diameter.
10÷2=5
Now let's plug it in.
4π(5³/3)
Let's solve.
4π= 12.56
5³= 125
125÷3= 41.67 (repeating 6)
41.67×12.56= 523.3752
523.33 cubic inches is the volume of air contained inside the beach ball. The reason I picked that answer is because we rounded up to 41.67, when there was a repeating 6. So we should expect for the answer to be a couple decimals lower from the answer we got.
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3 years ago
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26. During a sale, a store offered a 20% discount on a particular camera that was originally priced at $450.
NARA [144]

Answer:

D.$315

Step-by-step explanation:

$450=100%

100%-20%-10%=70%

$450×70%=$450×70/100

=$315

7 0
3 years ago
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What is the simplified sum of 3x/x-4 + x-3/2x
zubka84 [21]

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▹ Answer

<em>-1 - 1/2x</em>

▹ Step-by-Step Explanation

3x ÷ x - 4 + x - 3 ÷ 2x

Divide and Rewrite:

3 * 1 - 4 + x - 3 ÷ 2 * x

Calculate:

3 - 4 + x - 3/2x

-1 + x - 3/2x

= -1 - 1/2x

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4 0
3 years ago
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Newborn babies: A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights
Fed [463]

Answer:

a) 615

b) 715

c) 344

Step-by-step explanation:

According to the Question,

  • Given that,  A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights of 732 babies born in New York. The mean weight was 3311 grams with a standard deviation of 860 grams

  • Since the distribution is approximately bell-shaped, we can use the normal distribution and calculate the Z scores for each scenario.

Z = (x - mean)/standard deviation

Now,

For x = 4171,  Z = (4171 - 3311)/860 = 1  

  • P(Z < 1) using Z table for areas for the standard normal distribution, you will get 0.8413.

Next, multiply that by the sample size of 732.

  • Therefore 732(0.8413) = 615.8316, so approximately 615 will weigh less than 4171  

 

  • For part b, use the same method except x is now 1591.    

Z = (1581 - 3311)/860 = -2    

  • P(Z > -2) , using the Z table is 1 - 0.0228 = 0.9772 . Now 732(0.9772) = 715.3104, so approximately 715 will weigh more than 1591.

 

  • For part c, we now need to get two Z scores, one for 3311 and another for 5031.

Z1 = (3311 - 3311)/860 = 0

Z2 = (5031 - 3311)/860= 2  

P(0 ≤ Z ≤ 2) = 0.9772 - 0.5000 = 0.4772

  approximately 47% fall between 0 and 1 standard deviation, so take 0.47 times 732 ⇒ 732×0.47 = 344.

5 0
3 years ago
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