Answer:
Umm... the population increased
Step-by-step explanation:
what is the question though.. .I mean what are we supposed to answer but The population increased 13000 after 10 years. hope that is what it you're asking for the answer and hope that helps ( :
Answer: The value of the expression when 
is 
Step-by-step explanation:
In this case, you need to remember that:
1. Tthe word "less than" indicates a subtraction.
2. By definition, the "Difference" in the result of a subtraction.
3. The word "times" indicates multiplication,
Based on the information given above, you know that " Six times the difference of a number and five" can be expressed as:
Then, "Two less than six times the difference of a number and five" can be represented with this expression:
Now you can substitute into the expression and the evaluate in order to find the value of the expression. This is:
The equation of the new path would be y=1/3x+4.
Explanation
If two lines are perpendicular, their slopes are negative reciprocals of each other. The original equation is written in slope-intercept form, y=mx+b, where m is the slope. In this equation, m=-3=-3/1.
In the new equation, the slope would be the opposite sign and flipped; this means it would be 1/3.
We can use the point given, the slope and slope-intercept form to write the equation of the new line:
y=mx+b
3=1/3(-3)+b
3=1/3(-3/1)+b
3=(-3/3)+b
3=-1+b
Add 1 to both sides:
3+1=-1+b+1
4=b
This makes the equation y=1/3x+4.
Using it's concept, it is found that the average rate of change of the function from x = -1 to x = 5 is of -1.
<h3>What is the average rate of change of a function?</h3>
It is given by the <u>change in the output divided by the change in the input</u>.
In this problem, the output changes by -6(from 7 to 1) when the input changes by 6(from -1 to 5), hence the average rate is given by:
r = -6/6 = -1.
More can be learned about the average rate of change at brainly.com/question/24313700
#SPJ1
Before you do anything, you convert 1/4 into 0.25. Then you start multiplying. If you don't understand email me at
[email protected] or go to Khan Academy .
