Answer:
Step-by-step explanation:
You can split the coins into 3 groups, each of them has 3 coins. Weigh group 1 vs group 2, if one is lighter, that group has the fake coin. If both groups weigh the same, then group 3 has the fake coin.
Continue to split the group that has the fake coin into 3 groups, each group has 1 coin. Now apply the same procedure and we can identify the fake coin.
Total of scale usage is 2
b) if you have 
coins then you can apply the same approach and find the fake coin with just n steps. By splitting up to 3 groups each step, after each step you should be able to narrow down your suspected coin by 3 times.
Step 1: you narrow down to group of 
coins
Step 2: you narrow down to group of 
coins
Step 3: you narrow down to group of 
coins
...
Step n: Step 1: you narrow down to group of 
coin
Answer: with question 1 mark your first line by having it intercept at postive 4 on y axis then count up 1 right 4 then mark a point then mark a point down 1 left 4 then create your line
After that line go to next line but starting at -3 on y axis then go up three left 2 until you cant fit on graph you should get your answer where both lines you draw cross at
Step-by-step explanation:
Answer:
32/40
Step-by-step explanation:
1: Sin= Soh
Soh= Opposite over Hypotenuse
2. A's opposite is 32
3. A's Hypotenuse is 40
4. A = 32/40
Answer: 45
Step-by-step explanation: To divide this start with finding how many times 585 goes into 13 which is 0. I put a picture for you to look at.
No:
At first, it might appear that the number with a leftmost digit of 8 should be bigger than one with a left most digit of 3 because so long as the 3 and 8 have the same digit position, this will be the case;
The same applies if the 3 is at a lower digit position than the 8;
But, there is nothing in the statement to suggest that the 8 has the higher digit position, i.e. the numbers could be 3000 and 800;
In this case, the largest number has the leftmost digit of 3;
Therefore, you cannot tell which number will be bigger without any other information.
