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Advocard [28]
3 years ago
9

Whats x+y=11 standard form to slope intercept form?

Mathematics
2 answers:
puteri [66]3 years ago
8 0

Answer:

Step-by-shwowbfizbaasldkt fbdisjs r fbfjep explanation:

adelina 88 [10]3 years ago
5 0
Slope intercept form: y= -x + 11

Why?
Subtract the x to get it on the other side:
x + y = 11
- x -x
y= -x + 11 ( make sure the variable is before the constant number)
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Can u please help me with 27
Pachacha [2.7K]
The answer would be 237.375. To get this answer, you will first use the formula given for each unit. First, you will do the first unit by putting 8 to the third power, or basically 8x8x8. After you get the product 512, you will then do the next unit. Do that one by doing 6.5 to the third power, or as followed, 6.5x6.5x6.5. Once you get the product 274.625, you will then subtract that from 512. You will then receive the answer 237.375.
5 0
3 years ago
Find the lowest common denominator.<br> 1/3 and 5/7<br> The lowest common denominator is
vagabundo [1.1K]
The lowest common denominator is 21
7 0
3 years ago
Select all true statements
bixtya [17]

Answer:

f(x) has a larger growth rate

f(x) is always greater than g(x)

Step-by-step explanation:

f(x) = 2/5 x

g(x) = -2x

the slope of f(x) when graphed is 2/5 x, which is a positive value making it a larger growth rate than g(x) and it also will always be greater since the value of f(x) is positive

therefore the correct true statements are:

f(x) has a larger growth rate, and f(x) is always greater than g(x)

8 0
3 years ago
Read 2 more answers
Help i need to know pls
alexira [117]

Answer:

7.8 =x

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp / adj

tan 48 = x/7

7 tan 48 = x

7.774287604 = x

To the nearest tenth

7.8 =x

4 0
3 years ago
Use Newton's method to find the second and third approximation of a root of x3+x+2=0 starting with x1=−1 as the initial approxim
adoni [48]

Answer:

The third approximation is x_3=-1.08259

Step-by-step explanation:

We are given that  

f(x)=x^3+x+2=0

x_1=-2

We have to find the second and third approximation of a root of given equation by using Newton's method.

We know that Newton's method , if nth approximation is given x_n and f'(x_n)\neq 0 then, the next approximation is given by  

x_{n+1}=x_n-\frac{f(x_n)}{f'(x_n)}

f'(x)=3x^2+1

Substitute x_1=-2

f(x_1)=f(-2)=(-2)^3+(-2)+2=-8

f'(x_1)=f'(-2)=3(-2)^2+1=13

Substitute the value n=1 then, we get  

x_2=x_1-\frac{f(x_1)}{f'(x_1)}

Substitute the values then , we get  the second approximation

x_2=-2-\frac{-8}{13}=-\frac{18}{13}

For n=2

f(x_2)=f(-\frac{18}{13})=(-\frac{18}{13})^3-\frac{18}{13}+2=-2.03914

f'(x_2)=f'(-\frac{18}{13})=3(-\frac{18}{13})^2+1=6.75148

x_3=x_2-\frac{f(x_2)}{f'(x_2)}

x_3=-\frac{18}{13}-\frac{-2.03914}{6.75148}=-1.08259

Hence, the third approximation is x_3=-1.08259

7 0
3 years ago
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