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densk [106]
3 years ago
9

What is the total surface area of the square pyramid below? question above ​

Mathematics
1 answer:
Wewaii [24]3 years ago
8 0

Answer:

132 m².

Step-by-step explanation:

What's the surface area of each lateral face of this pyramid?

Each lateral face of this pyramid is a triangle, with

  • a height of 8 meters
  • on a base 6 meters.

The base of this pyramid is a square. As a result, all four lateral sides are congruent. The area of each of these triangle is thus

\displaystyle \frac{1}{2}\times \text{Base}\times \text{Height} = \rm \frac{1}{2} \times 6 \times 8 = 24\; m^{2}.

The base of this pyramid is a square. The length of a side of this square is 6 meters. The area of the base will be

\text{Side}^{2} = \rm 6^{2} = 36\; m^{2}.

Put the five faces together to get the total surface area of this square pyramid:

\rm 4\times 24 + 36 = 132\; m^{2}.

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If you have 1275 ÷ 4, you write it as shown, with 1275 on the inside and 4 on the outside. then you go digit by digit and find how many times 4 goes into the number. it goes into 1 zero times, so an imaginary 0 is put in the first spot above the 1. next, 4 goes into 12 three times, so 3 is written above the 2. After that, subtract 4×3 from 12, which leaves 0, and bring down the 7. 4 goes into 7 once with a remainder of 3, so a 1 is put up top and the 5 brought down next to the three. 4 goes into 35 eight times with a remainder of 3,so 8 is written up top. the 3 is the remainder, written as R3. so your answer is 1274÷4= 318 R3.
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