Please help us!!we really need gwlp
Here are the steps.
In order to get the answer, first we need to get the x and y value of the center of the circle by using the equation of a circle (x^2 + y^2 = r^2)
<span>The center is (-9, -4)</span>
Once you get the center point, find the equation of the line (in a form of a radius) from the center point to point (2, -1). Get the slope.
The slope from center to point (2, -1) is 11/3
Finally, get the negative reciprocal of the slope from the previous step and form the equation using slope-intercept form ( y=mx + b). Then, that's the equation of the tangent line.
The slope of the tangent line is -3/11
The equation is y = -3/11x - 5/11
Answer: 1.4 seconds
<u>Step-by-step explanation:</u>
The equation is: h(t) = at² + v₀t + h₀ where
- a is the acceleration (in this case it is gravity)
- v₀ is the initial velocity
- h₀ is the initial height
Given:
- a = -9.81 (if it wasn't given in your textbook, you can look it up)
- v₀ = 12
- h₀ = 3
Since we are trying to find out when it lands on the ground, h(t) = 0
EQUATION: 0 = 9.81t² + 12t + 3
Use the quadratic equation to find the x-intercepts
a=-9.81, b=12, c=3
Note: Negative time (-0.2) is not valid
Answer:
2^3×3^2
and yh
Step-by-step explanation:
2×2×2×3×3
Answer:
5.25 and for the second part 126
Step-by-step explanation:
trust
