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2 years ago

11

PLS HELP ILL GIVE BRAINLIEST

2 answers:

trasher [3.6K]2 years ago

8 0

Answer:

y=1/3x+4

Step-by-step explanation:

y=2-3x is equivilent to y=-3x+2

Here were see that the coefficient of x is -3. In order to find a line that is perpendicular to another line, we need to put the opposite sign and make the coefficient the reciprical.

So now we know that y=1/3x will be perpendicular to your line. If the point goes through (0,4) that means when x is zero, y is 4. If we plug that into our expression 4=1/3*0, we see that we need to add 4 to make this true.

So our answer is y=1/3x+4

Sati [7]2 years ago

5 0

The answer is y = 1/3x + 4. -3x repricdal = 1/3. 4=1/3(0) + 4

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A cable hangs between two poles of equal height and 35 feet apart. At a point on the ground directly under the cable and x feet

gayaneshka [121]

Answer:

293.38 pounds

Step-by-step explanation:

We are given that

Distance between poles=35 feet

$h(x)=10+0.1(x^{1.5})$

Weight of cable=10.4 per linear foot

We have to find the weight of the cable.

Differentiate w.r.t

$h'(x)=0.1(1.5)x^{0.5}=0.15x^{0.5}$

$s=2\int_{0}^{17.5}\sqrt{1+(h'(x))^2}dx$

$s=2\int_{0}^{17.5}\sqrt{1+(0.15x^{0.5})^2}dx$

$s=2\int_{0}^{17.5}\sqrt{1+0.0225x}dx$

Let $1+0.0225x=t$

$dx=\frac{1}{0.0225}dt$

$s=\frac{2}{0.0225}\int_{0}^{17.5}\sqrt{t}dt$

$s=\frac{2}{0.0225}\times\frac{2}{3}[t^{\frac{3}{2}}]^{17.5}_{0}$

$s=2\times \frac{2}{3\times0.0225}[(1+0.0255x)^{\frac{3}{2}]^{17.5}_{0}$

$s=\frac{4}{3\times 0.0225}((1+0.0225(17.5))^{\frac{3}{2}-1)$

s=28.21

Weight of cable= $28.21\times 10.4=293.38$ pound

8 0

3 years ago

Please help me .!<br> 10 points .!

BaLLatris [955]

The answer is 19 I subtracted the 2 biggest numbers

5 0

3 years ago

In Arizona, a minimum temperature of -40°F was recorded at Hawley Lake 1971. A maximum recorded

ddd [48]

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2 years ago

. A landscaping company charges $40 to mow a lawn and $15 per hour to weed garden beds. The

Murljashka [212]

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3 years ago

What are the solutions of the quadratic equation? 4x^2+34x+60=0

insens350 [35]

Answer:

Option 3) -6,-5/2

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$4x^{2} +34x+60=0$

so

$a=4\\b=34\\c=60$

substitute in the formula

$x=\frac{-34(+/-)\sqrt{34^{2}-4(4)(60)}} {2(4)}$

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$x=\frac{-34(+/-)14} {8}$

$x_1=\frac{-34(+)14} {8}=-\frac{20}{8}=-\frac{5}{2}$

$x_2=\frac{-34(-)14} {8}=-6$

6 0

3 years ago