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nadya68 [22]
3 years ago
10

How do you write 4.293 in expanded form?

Mathematics
1 answer:
Anika [276]3 years ago
3 0
4.000 plus 200 plus 90 plus 3
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Solve the equation: <br> 1.)     y/6 + 12 = (-12)<br> 2.)     y/3 - 4 = (-20)
vivado [14]

I am sorry but what level is this


4 0
3 years ago
A shed has dimensions of 12m in length and 5 m in width. Both the length and width are increased by the same amount in order to
mestny [16]

The amount by which the length and width of a shed can be increased to

more than double the area, depends on the initial dimensions.

  • The amount that can be added to both the length and the width to increase the floor area by more than double the original area is more than <u>3 meters</u>.

Reasons:

The given parameters of the shed are;

The length of the shed = 12 m

Width of the shed = 5 m

The amount by which the length and the width are increased = The same amount

The new area after the increase in the length and width of the shed = More than double the initial area

Required:

The amount of increase in the length.

Solution:

Let the amount by which the length and width are increased = x

We have;

Initial area of the shed = 12 m × 5 m = 60 m²

The new area = (12 + x) × (5 + x) > 2 × 60

By multiplication, we get;

(12 + x) × (5 + x) = x² + 17·x + 60 > 2 × 60 = 120

x² + 17·x + 60 - 120 > 120 - 120 = 0

x² + 17·x - 60 > 0

By factorization, we get;

(x + 20)·(x - 3) > 0

x > -20, or x > 3

The increase (positive) amount of the solution is x > 3

Therefore, <u>the amount by which both the length and the width can be increased to more than double the area is x > 3 meters</u>

Learn more about the area of a rectangle here:

brainly.com/question/16410706

7 0
2 years ago
a mustard seed has a mass of about 0.002 grams a glas jar contains about 4.3602x10e4 seeds what is a estimate of the mass of the
san4es73 [151]

Answer:

It has to 4.3 because u divided it from the sum to get the  an porportional answer so u had to solve it from a measurement on how many seeds does which the mass revolves around

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
PLS!
Mars2501 [29]

Answer:

Enterprise charges more for a 6 day rental.  ($284 for Hertz and $294 for Enterprise). Avery would save $4 if he rented with Hertz for 4 days.

Step-by-step explanation:

H = Hertz

E = Enterprise

x = Days rented

T = Total cost for x days, in $

<u>Hertz:</u>   TH = 42x + 32

<u>Enterprise: </u> TE= 45x + 24

====================

6 Day Rental:

TH = 42*(6) + 32,    =  $284

TE  = 45*(6) + 24     =  $294

4 Day Rental:

TH = 42*(4) + 32,    =  $200

TE  = 45*(4) + 24     =  $204

<u></u>

<u></u>

4 0
3 years ago
How to do this question plz ​
hjlf

Answer:

\underline{ \boxed{ \underline{part \: a}}}. \\the \: required \: distance  \: a part \: be \to \:  \boxed{\underline {\overline{p }  =79.23 \: km} }  \\  \\ \underline{ \boxed{ \underline{part \: b}}}. \\ the \: bearing \: of \: \boxed{ B } \: \: from \:  \boxed{ \underline{A}} \: is \to \boxed{ \underline{324 }\degree }

Step-by-step explanation:

\underline{ \boxed{ \underline{part \: a}}}. \\  l et \: the \: required \: distance  \: apart \: be \to \:  \boxed{ \overline  {p}} \\ let \:  \boxed{ \angle \: P} \: be \: the \: angle \: of \: seperation \: between \: both \: ships  :given \: by \to \\  P = (244 - 180) - (196 - 180 )= (64 -16) =  \boxed{48 \degree} \\ if \: ship \: A \: and \: B \: left  \: the \: port\: at \: (10:30) \:  \\ then \: at \: (14 :00) \: their \: time \: interval \: would \: be \to \\ (14 : 00) - (10 : 30) = \boxed{ 3.5 \: hrs} \\ ship \:  \boxed{A }\: distance \: from \: the \: port =( v \times t) = (30 \times 3.5) =  \boxed{105 \: km} \\ ship \:  \boxed{B }\: distance \: from \: the \: port =( v \times t) = (24 \times 3.5) =  \boxed{84\: km} \\n ow........we \: cant \: do \: much \: if \: their \: are \: no \: angles \: to \: work \: with \to \\ applying \:t he \: cosine \: rule : we \: have \to \\  \cos(P)  =  \frac{ {a}^{2} +  {b}^{2}  -  \overline{{p}^{2} } }{2(ab)}  \\  {a}^{2} +  {b}^{2}  -  \overline{{p}^{2} } = 2(ab) \cos(P)  \\ \overline{{p}^{2} } = {a}^{2} +  {b}^{2}  - \{2(ab) \cos(P)  \} \\ \overline{{p}^{2} }  =  {84}^{2}  +  {105}^{2}  -  \{2(84)(105) \cos(48 \degree)  \} \\\overline{{p}^{2} }  =  18,081 - 11,803.463897 \\ \overline{{p}^{2} }  = 6,277.536103 \\ \overline{p }  =  \sqrt{6,277.536103} \\  \boxed{\underline {\overline{p }  =79.23 \: km} } \\  \\  \underline{ \boxed{ \underline{part \: b}}}. \\ to \: sove \: this : we \: first \: find \:  angle \: \angle \: B : by \: applying \to \\  \frac{ \sin(B) }{b}  = \frac{  \sin(P) }{p}  \\  p \ast \sin(B)  = b \ast \sin(P) \\ B =  \sin {}^{ - 1} ( \frac{ b \ast \sin(P)}{p} )  \\ B =  \sin {}^{ - 1} ( \frac{ 105 \times  \sin(48 \degree)}{79.230903712} )  \\  \\ B =  \sin {}^{ - 1} ( \frac{ 78.030206678}{79.230903712} )    \\ \\ B =  \sin {}^{ - 1} (0.9848455971) \\  \boxed{B =  80 \degree} \\ hence \ :  the \: bearing \: of \: \boxed{ B } \: \: from \:  \boxed{ \underline{A}} \: is \to \\ 360 -  \{180 - (80 + 48 + 16) \} \\ 360 -(180 - 144 )\\ 360 -36 =   \boxed{324 \degree }

♨Rage♨

7 0
3 years ago
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