Answer:
hope it helps forget about my writing
Sure! So this is ready as "the cube root of 125". This basically means, "what number cubed can get me 125?"
Let's go through our options.
We can rule out D, as D cubed would be unreasonably big.
We can also rule out C, because 375 cubed is easily over 10000, you know this even if you haven't computed it all, just compute the 300 cubed.
We can rule out B, too. 41 squared is already over 125, therefore it can't be the answer.
Therefore our answer is A, 5. We can check that by cubing 5, and that indeed gets us 125.
Hope this helps!
Answer: A
Step-by-step explanation:
To solve this problem, think of a coordinate plane. Look at the first x and y on the table. The x is zero and the y is 8. Now look at the answers. For x to be zero while y has a value would mean that it would have a y-intercept of 8. The only answer that has a y-intercept of that value is A.
To prove that A is the correct problem, try to do slope intercept with it. The slope is 9, so the y increases by 9 and the x increases by 1. 8 + 9 is 17, which is the second y. 0 + 1 is 1, which is the second x. So A must be the correct answer.
Answer:
There are 36 cubes
Step-by-step explanation:
Answer:
She must consider 3507 components to be 90% sure of knowing the mean will be within ± 0.1 mm.
Step-by-step explanation:
We are given that an engineer wishes to determine the width of a particular electronic component. If she knows that the standard deviation is 3.6 mm.
And she considers to be 90% sure of knowing the mean will be within ±0.1 mm.
As we know that the margin of error is given by the following formula;
The margin of error = 
Here, 
= standard deviation = 3.6 mm
n = sample size of components
= level of significance = 1 - 0.90 = 0.10 or 10%
= 0.05 or 5%
Now, the critical value of z at a 5% level of significance in the z table is given to us as 1.645.
So, the margin of error =
0.1 mm = 
= 59.22
n = 
= 3507.0084 ≈ 3507.
Hence, she must consider 3507 components to be 90% sure of knowing the mean will be within ± 0.1 mm.
