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d1i1m1o1n [39]
3 years ago
11

Please answer this I give brainliest! :-) No responding fake answers, will be reported to the service:

Mathematics
1 answer:
Mrrafil [7]3 years ago
3 0

Answer:

c=35 + 25m

Step-by-step explanation:

Sorry, that's all I got

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20 POINTS ASAP 16 = 2^x − 2 <br><br>a)2 <br><br>b)4 <br><br>c)6 <br><br>d)8
Lilit [14]

Answer:

4

Step-by-step explanation:

Exact Form:

x

=

ln( 18)

---------

ln (2)

Decimal Form:

x=4.16992500

…

8 0
3 years ago
HELPPP!!!!<br><br> Complete the​ two-column proof by filling in the blanks.
Brilliant_brown [7]

Answer:

2. Substitution property

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Step-by-step explanation:

4 0
3 years ago
For f(x)=13^x,find f(3/2)
tekilochka [14]

Answer:

  f(3/2) = 13√13 ≈ 46.872167

Step-by-step explanation:

Put 3/2 where x is and evaluate.

  f(3/2) = 13^(3/2) = 13^(1 +1/2) = 13√13

  f(3/2) ≈ 46.872167

5 0
3 years ago
What is the solution of 5 = t/2 -3?
Sladkaya [172]

Answer:

t=16

Step-by-step explanation:

you have to change the numbers to get just the variable.

we start from -3.

5=t/2-3

8=t/2

(we multiply by 2 instead of dividing)

8×2=16

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5 0
3 years ago
An Article a Florida newspaper reported on the topics that teenagers most want to discuss with their parents. The findings, the
Sergio039 [100]

Answer:

The estimate is  P__{hat}} \pm E  = 0.37 \pm 0.0348

Step-by-step explanation:

From the question we are told that  

    The sample size is  n =  522

    The sample proportion of students  would like to talk about school is  \r p__{hat}} =  0.37

  Given that the confidence level is  90 % then the level of significance can be mathematically evaluated as

                  \alpha  =  100 - 90

                  \alpha  =  10\%

                  \alpha  =  0.10

Next we obtain the critical value of  \frac{\alpha }{2} from the normal distribution table, the value is  

               Z_{\frac{\alpha }{2} } =Z_{\frac{0.10}{2} } =  1.645

Generally the margin of error can be mathematically represented as

               E =  Z_{\frac{\alpha }{2} } *  \sqrt{\frac{\r P_{hat}(1- \r P_{hat} )}{n } }

=>            E = 1.645 *  \sqrt{\frac{0.37 (1- 0.37  )}{522 } }

=>             E = 0.0348

Generally the estimate the proportion of all teenagers who want more family discussions about school at 90% confidence level is  

                       P__{hat}} \pm  E

substituting values

                     0.37 \pm 0.0348

5 0
3 years ago
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