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Eva8 [605]
4 years ago
13

!!!50 POINTS!!! Help Please 2. Which functions are exponential decay functions? Choose exactly two answers that are correct. A.

f(x)=0.9^x B. g(x)=(6/5)^x C. h(x)=1.25^x D. j(x)=(4/5)^x
Mathematics
1 answer:
Goshia [24]4 years ago
5 0
A characteristics of an exponential decay function is it has a constant term that is lesser than 1, this is because when you raise it a number that is lesser than 1 to higher values the result will be lesser and lesser, that is why it is called decay function. so the decay functions are a. f(x)=0.9^x and d. <span>j(x)=(4/5)^x</span>
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A set of data is summarized by the stem and leaf plot below.
Andre45 [30]

Answer:

30 values ; greater than or equal to 10 and less Than or equal to 39

Step-by-step explanation:

Counting the number of leaves in the plot, we have 30 leaf values. This gives the number of dataset.

The minimum value is the number created by the combination of the least stem value and the lowest leaf value, which is 10

The maximum value is obtained from the combination of the highest stem and leaf value. The highest value is 39

8 0
3 years ago
Sheila bought 10 1⁄2 oz of almonds for $3.36. how much did the almonds cost per ounce?
Verdich [7]
Cost per ounce means you take the cost and divide it by the cost: 

<span>3.36 / (21/2) </span>

<span>division of fractions changes to the multiplication of the reciprocal: </span>

<span>3.36 * (2 / 21) </span>

<span>3.36 and has 21 as a factor, so let's cancel it: </span>

<span>0.16 * 2 </span>

<span>$0.32 per ounce</span>
4 0
3 years ago
The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 55 o
Usimov [2.4K]

Answer:

a) For this case and using the empirical rule we can find the limits in order to have 9% of the values:

\mu -2\sigma = 55 -2*6 =43

\mu +2\sigma = 55 +2*6 =67

95% of the widget weights lie between 43 and 67

b) For this case we know that 37 is 3 deviations above the mean and 67 2 deviations above the mean since within 3 deviation we have 99.7% of the data then the % below 37 would be (100-99.7)/2 = 0.15% and the percentage above 67 two deviations above the mean would be (100-95)/2 =2.5% and then we can find the percentage between 37 and 67 like this:

100 -0.15-2.5 = 97.85

c) We want to find the percentage above 49 and this value is 1 deviation below the mean so then this percentage would be (100-68)/2 = 16%

Step-by-step explanation:

For this case our random variable of interest for the weights is bell shaped and we know the following parameters.

\mu = 55, \sigma =6

We can see the illustration of the curve in the figure attached. We need to remember that from the empirical rule we have 68% of the values within one deviation from the mean, 95% of the data within 2 deviations and 99.7% of the values within 3 deviations from the mean.

Part a

For this case and using the empirical rule we can find the limits in order to have 9% of the values:

\mu -2\sigma = 55 -2*6 =43

\mu +2\sigma = 55 +2*6 =67

95% of the widget weights lie between 43 and 67

Part b

For this case we know that 37 is 3 deviations above the mean and 67 2 deviations above the mean since within 3 deviation we have 99.7% of the data then the % below 37 would be (100-99.7)/2 = 0.15% and the percentage above 67 two deviations above the mean would be (100-95)/2 =2.5% and then we can find the percentage between 37 and 67 like this:

100 -0.15-2.5 = 97.85

Part c

We want to find the percentage above 49 and this value is 1 deviation below the mean so then this percentage would be (100-68)/2 = 16%

4 0
4 years ago
Estimate by first rounding each number to the nearest . 1/2 3 4/11 2 1/10
Sonbull [250]
1/2 can't be rounded so its 1/2 still. 
3 4/11 rounds to 3.
2 1/0 rounds to 2.
6 0
3 years ago
What is this answer to this question
Rus_ich [418]

Answer:

The answer to 237 × 401 is <u>95037</u>

5 0
3 years ago
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