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Ahat [919]
3 years ago
5

David helped his father stock the pond with baby catfish and blue gill. They put in a total of 75 fish. If the number of blue gi

ll was doubled and the number of catfish tripled, there would be 175 fish in the pond. How many catfish were put in the pond?
Mathematics
2 answers:
lana [24]3 years ago
6 0
x-\ amount\ of\ catfish\\\\
y-\ amount\ of\ blue\ gill\\\\\ 
 \left \{ {{x+y=75} \atop {2y+3x=175}} \right. |using\ substitution\ method:\ x=75-y\\\\
2y+3(75-y)=175\\
2y+225-3y=175\\
-y=-50\ \ |*(-1)
y=50\\
x=75-50=25\\
there\ were\ 25\ catfish\ put\ in\ the\ pond
serious [3.7K]3 years ago
4 0
You have to work this out through a process of trial and error. Firstly, let's start simple, by dividing the 175 by 5. 5 because if the number of blue gill is doubled and catfish tripled, there will be five groups rather than two, three of the groups being identical, and the other two also being identical.

175/5 = 35
35 x 2 = 70 x

As you can see, this hasn't worked, as the original amount ends up being 70 rather than 75. Now try again. Split the 175 up into two numbers, one that is divisible by three, the other that is divisible by two. For example, 100 and 75.

100/2 = 50
75/3 = 25
50 + 25 = 75

This way worked, though usually you might have to go on guessing for quite a while. The original amount of catfish in the pond would be 25 (because the number of catfish was tripled and the 75 was divided by three).
So yeah, the answer's 25. Hope that helped. Let me know if there's anything I need to explain better ;)
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2 years ago
What is the x- intercept of the line?
valentinak56 [21]

Answer:

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Step-by-step explanation:

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3 years ago
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Kryger [21]
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3 years ago
What is the equation of the line that passes through (1, 2) and is parallel to the line whose equation is 4x + y + 1 = 0?
Bezzdna [24]

Answer:

The answer is

<h2>4x + y - 6 = 0</h2>

Step-by-step explanation:

Equation of a line is y = mx + c

where m is the slope

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y = - 4x - 1

Comparing with the above formula

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Since the lines are parallel their slope are also the same

That's

Slope of the parallel line is also - 4

Equation of the line using point ( 1 , 2) is

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We have the final answer as

<h3>4x + y - 6 = 0</h3>

Hope this helps you

7 0
3 years ago
Use a proof by contradiction to show that the square root of 3 is national You may use the following fact: For any integer kirke
Ierofanga [76]

Answer:

1. Let us proof that √3 is an irrational number, using <em>reductio ad absurdum</em>. Assume that \sqrt{3}=\frac{m}{n} where  m and n are non negative integers, and the fraction \frac{m}{n} is irreducible, i.e., the numbers m and n have no common factors.

Now, squaring the equality at the beginning we get that

3=\frac{m^2}{n^2} (1)

which is equivalent to 3n^2=m^2. From this we can deduce that 3 divides the number m^2, and necessarily 3 must divide m. Thus, m=3p, where p is a non negative integer.

Substituting m=3p into (1), we get

3= \frac{9p^2}{n^2}

which is equivalent to

n^2=3p^2.

Thus, 3 divides n^2 and necessarily 3 must divide n. Hence, n=3q where q is a non negative integer.

Notice that

\frac{m}{n} = \frac{3p}{3q} = \frac{p}{q}.

The above equality means that the fraction \frac{m}{n} is reducible, what contradicts our initial assumption. So, \sqrt{3} is irrational.

2. Let us prove now that the multiplication of an integer and a rational number is a rational number. So, r\in\mathbb{Q}, which is equivalent to say that r=\frac{m}{n} where  m and n are non negative integers. Also, assume that k\in\mathbb{Z}. So, we want to prove that k\cdot r\in\mathbb{Z}. Recall that an integer k can be written as

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Then,

k\cdot r = \frac{k}{1}\frac{m}{n} = \frac{mk}{n}.

Notice that the product mk is an integer. Thus, the fraction \frac{mk}{n} is a rational number. Therefore, k\cdot r\in\mathbb{Q}.

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Write q=x+p and let us suppose that q is a rational number. So, we get that

x=q-p.

But the subtraction or addition of two rational numbers is rational too. Then, the number x must be rational too, which is a clear contradiction with our hypothesis. Therefore, x+p is irrational.

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