It's elimination linear equations -x+y=-2

Why don’t Noble Gases have a value for electronegativity?

kumpel [21]

Answer:

The answer is 1.

Step-by-step explanation:

Nobel gases have full shell of valence electrons, that is why they tend to not enter any chemical reactions because they are satisfied while metals have very few electrons in the valence shell, so they are active in any chemical reaction.

7 0

3 years ago

A fruit stand has to decide what to charge for their produce. They need $ 5 for 1 apple and 1 orange. They also need $ 15 for 3

sineoko [7]

Answer:

2 and 3

If you want to get complicated, then 2.39 and 2.61.

Step-by-step explanation:

5 = x + y

5 = 2 + 3

5 = 5

5 0

2 years ago

When completely factored x²-x-12 is equivalent to which of the following

QveST [7]

Answer:

$→{x}^{2} - x - 12 \\ = {x}^{2} - 4x + 3x - 12 \\ = x(x - 4) + 3(x - 4) \\ = \boxed{ (x - 4)(x + 3)}✓$

<u>D. (x</u><u> </u><u>-</u><u> </u><u>4)(x</u><u> </u><u>+</u><u> </u><u>3)</u> is the right answer.

4 0

3 years ago

What is the speed of the car that travels 2955 km in 13 hours?

beks73 [17]

<h3>Hello There!!</h3>

<u>Given,</u>

Distance (d)= 2955 km

Time (t)= 13 hr

Speed (s)=?

<h2><u>Solution</u></h2>

$s = \frac{d}{t} \\ \\ s = \frac{2995}{13} \\ \\ s = 227.308 \: \: \text{km/hr}$

Rounding To Nearest Whole Number= 227 Km/hr

$\therefore \text{speed} = 227 \text{km/hr}$

<h3>Hope This Helps</h3>

5 0

2 years ago

Read 2 more answers

Please help with this problem.

larisa86 [58]

Answer:

60°, 120°

Step-by-step explanation:

$\frac{ {tan}^{2}x }{2} - 2 {cos}^{2}x = 1 \\ \\ \frac{ {tan}^{2}x - 4{cos}^{2}x }{2} = 1 \\ \\ {tan}^{2}x - 4{cos}^{2}x = 2 \\ \\ \frac{{sin}^{2}x}{{cos}^{2}x} - 4{cos}^{2}x = 2 \\ \\ \frac{{sin}^{2}x - 4{cos}^{4}x}{{cos}^{2}x} = 2 \\ \\ {sin}^{2}x - 4{cos}^{4}x = 2{cos}^{2}x \\ \\ 4{cos}^{4}x + 2{cos}^{2}x - {sin}^{2}x = 0 \\ \\ 4{cos}^{4}x + 2{cos}^{2}x + {cos}^{2}x - 1= 0 \\ \\ 4{cos}^{4}x + 3{cos}^{2}x - 1= 0 \\ \\ 4{cos}^{4}x + 4{cos}^{2}x - {cos}^{2}x - 1= 0 \\ \\4{cos}^{2}x({cos}^{2}x + 1) - 1({cos}^{2}x + 1) = 0 \\ \\ ({cos}^{2}x + 1)(4{cos}^{2}x - 1) = 0 \\ \\ ({cos}^{2}x + 1) = 0 \: or \: (4{cos}^{2}x - 1) = 0 \\ \\ {cos}^{2}x = - 1 \: or \: 4{cos}^{2}x = 1 \\ \\ {cos}x = \sqrt{ - 1} \: which \: is \: not \: possible \\ \therefore \: {cos}^{2}x = \frac{1}{4} \\ \\ \therefore \: {cos}x = \pm\frac{1}{2} \\ \\ \therefore \: {cos}x = \frac{1}{2} \: or \: {cos}x = - \frac{1}{2} \\ \\ \therefore \: {cos}x = {cos}60 \degree \: or \: {cos}x = {cos}120 \degree \\ \\ \therefore \:x = 60 \degree \: \: or \: \: x = 120 \degree$

6 0

3 years ago