Answer:
C. ATP is generated
Explanation:
The Entner-Doudoroff pathway is one of the three glycolytic pathways that breakdown glucose into pyruvate. The Entner-Doudoroff pathway is the most common glycolytic pathway in microbes present in the soil such as <em>Rhizobium, Azotobacter,</em> etc.
The Entner-Doudoroff pathway forms glucose 6-phosphate from glucose which in turn is oxidized into 6-phosphogluconate. The 6-phosphogluconate finally forms pyruvate and glyceraldehyde 3-phosphate through a series of reactions. The glyceraldehyde 3-phosphate can enter the Embden-Meyerhof pathway to form one more molecule of pyruvate. During the Entner-Doudoroff pathway, one molecule of ATP and one NADPH are formed along with the formation of one molecule of each pyruvate and glyceraldehyde.
Answer:
Tt - 2/4 = 1/2 or 50% Heterozygous TALL
tt - 2/4 = 1/2 or 50% Homozygous Dwarf
Explanation:
So let's make a Punnett for this so you can see what the outcome is yourself:
Tall is <u>dominant</u> - T
Dwarf is <u>recessive</u> - t
Heterozygous means that they have one of each allele. The genotype of one parent would be then Tt.
***It is heterozygous tall because Tall is a dominant trait so if it is accompanied by the recessive trait dwarf, then the Tall allele would mask it.
The other parent is a dwarf plant. The genotype would then be tt.
*** Now for a recessive trait to appear, it should not have a dominant trait mixed with it, which could mask it. The result then is homozygous recessive or homozygous Dwarf.
So now that we know the genotypes of the parent plants, we can put it into a Punnet:
t t
T Tt Tt
t tt tt
As you can see, out of the 4 outcomes we have:
Tt - 2/4 = 1/2 or 50% Heterozygous TALL
tt - 2/4 = 1/2 or 50% Homozygous Dwarf
Organic materials less than "50,000 years" old are the type of materials that scientists would date with the carbon-14 method.
Answer:
The pH of a solution containing 0.1 mM H+ is 4
Explanation:
The pH of any solution is given by the following mathematical equation -
![pH = -log[H_{+}]\\](https://tex.z-dn.net/?f=pH%20%3D%20-log%5BH_%7B%2B%7D%5D%5C%5C)
----------- Equation (A)
Where,
= the concentration of hydrogen ion in the solution.
Given
= 
Substituting the given value in equation (A) , we get -
![pH = -log[10^{-4}]](https://tex.z-dn.net/?f=pH%20%3D%20-log%5B10%5E%7B-4%7D%5D)
Hence, The pH of a solution containing 0.1 mM H+ is 4
