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Firlakuza [10]
3 years ago
10

Lola bought x pencils that cost $0.25 each and y erasers that cost $0.50. She spent less than $3. Which graph represents Lola’s

purchase?

Mathematics
2 answers:
Amiraneli [1.4K]3 years ago
6 0

Answer:

Inequality is 0.25x+0.5y\leq 3 and the graph is shown below.

Step-by-step explanation:

Let the number of pencils bought = x and the number of erasers bought = y.

Now, Cost of 1 pencil = $0.25. So, the cost of x pencils = 0.25x dollars

Also, Cost of 1 eraser = $0.5. So, the cost of y erasers = 0.5y dollars

Since, she spent less than $3.

So, we have the inequality,

Cost of x pencils + Cost of y erasers ≤ Maximum amount spent

i.e. 0.25x+0.5y< 3

So, the graph representing the inequality is given below.

Nady [450]3 years ago
4 0
X would have to be less than 12, y would have to be less than 6. So a graph displaying x less than or equal to 12 and y less than or equal to 6.
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The common difference in an arithmetic sequence is –2 and the first term is 47. What is the 29th term?
BlackZzzverrR [31]

An arithmetic sequence is an ordered list of numbers where the next number is found by adding on to the last number (ex: 2,5,8,11... is a sequence where 3 is added on to find the next number).

The equation for an arithmetic sequence is
A_{n}=A_{1}+(n-1)d

A_{n} is the "n-th" number in the sequence (ex:  is the first term in the sequence)
d is the number you add (common difference) to find the next number
The first number in the sequence is 47 so A_{1}=47
<span>d=-2 because the question gives you that
</span>
A_{n}=A_{1}+(n-1)d
<span>A_{29}=47+(29-1)(-2)
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</span><span>A_{29}=47+-56
</span><span>A_{29}=-9
</span>
The answer is A. -9.

<u>                                                       </u>

<span>The answer is C. 158</span>

For the second one, it gives you A_{1}=4 and <span>A_{}=18
You can use this to find d

</span><span>A_{n}=A_{1}+(n-1)d
</span><span>A_{3}=4+(3-1)d
</span><span>18=4+(3-1)d
</span><span>18=4+2d
</span><span>14=2d
</span><span>7=d
</span>
Now you can just solve using the equation normally.
<span>A_{n}=A_{1}+(n-1)d
</span><span>A_{23}=4+(23-1)(7)
</span><span>A_{23}=4+(22)(7)
</span><span>A_{23}=4+154
</span><span>A_{23}=158
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The answer is C. 158
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We are given that

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