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bonufazy [111]
3 years ago
7

Choose the answer that validates that the rate of change is constant by showing that the ratios of the two quantities are propor

tional and equivalent to the unit rate (simplified constant rate of change): NUMBER OF TEXTBOOKS Number of Students Number of Textbooks 7 35 14 70 21 105 28 140
Mathematics
1 answer:
docker41 [41]3 years ago
8 0

Given:

The table of values is

Number of Students   :  7    14   21    28

Number of Textbooks : 35  70  105  140

To find:

The rate of change and showing that the ratios of the two quantities are proportional and equivalent to the unit rate.

Solution:

The ratio of number of textbooks to number of students are

\dfrac{35}{7}=5

\dfrac{70}{14}=5

\dfrac{105}{21}=5

\dfrac{140}{28}=5

All the ratios of the two quantities are proportional and equivalent to the unit rate.

Let y be the number of textbooks and x be the number of students, then

\dfrac{y}{x}=k

Here, k=5.

\dfrac{y}{x}=5

y=5x

Hence the rate of change is constant that is 5.

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8(14) = 112

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Please help me guys like I really need it
Lesechka [4]

Inequality 1: y ≤ 5x + 1

Inequality 2: y > x - 2


#1. The slope is 5, the y-intercept is 1, the shaded area is below the line and the line is solid, which means that y is less than or equal to the equation. (you add the "equal to" because the line is a solid line)

#2. The slope is 1, the y-intercept is -2, the shaded area is above the line and the line is dotted, which means that y is greater than the equation

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3 years ago
Which statement is supported by the histograms? The two data sets have the same distribution and same range. The two data sets h
Ad libitum [116K]

Answer:

The two data sets have different distributions and different ranges.

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5 0
3 years ago
Please show work!!!!!!!
kolezko [41]

Answer:

B

Step-by-step explanation:

The cylindrical part

Area of the cylindrical part = Circumference of the circle * height

Area of the cylindrical part = pi * d * height

Area = 3.14 * 10 * 9

Area =                                                                                282.6

Lid

Area = pi * r^2

r = 5

Area = 3.14* 5^2 * 2

Area =                                                                         <u>         157</u>

Total                                                                                    439.6                                                                        

I know this doesn't look right according to the diagram, but it is the only way that you can solve the question. That is, you must assume there are two lids, not one as the diagram suggests.

4 0
3 years ago
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