Answer:
The 99% confidence interval for the population mean reduction in anxiety was (1.2, 8.6).
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 27 - 1 = 26
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 26 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.7787.
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 4.9 - 3.7 = 1.2.
The upper end of the interval is the sample mean added to M. So it is 4.9 + 3.7 = 8.6.
The 99% confidence interval for the population mean reduction in anxiety was (1.2, 8.6).
No soy muy buena con álgebra pero te recomiendo esta app que se llama “Symbolab” donde solo tienes que escanear la tarea y te da la respuesta.
To get your answer, you would divide your distance by your speed. You should be going about 1.4 miles per hour.
I believe the answer is 120. 3 5/6 turns into 3.833 when turned into a decimal. 3.833 would round up to 4 which is the nearest whole number. 34 3/7 would turn into 34.4285 as a decimal which turns into 30 when rounded to the nearest ten.