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hram777 [196]
3 years ago
9

Question 5 How to solve it

Mathematics
1 answer:
svlad2 [7]3 years ago
5 0
Use the Angle measurements to find x measure
You might be interested in
State that dgree of the term -6x²y​
vladimir2022 [97]
I think it’s -6 but I would check with someone else too lol
3 0
4 years ago
What is the range of the function f(x)=3.2x for the domain {-4,-2,0,2,4}
just olya [345]

Answer:

Option A.  \{-12.8,-6.4,0,6.4,12.8\}

Step-by-step explanation:

we have

f(x)=3.2x

we know that

To find the range, substitute each value of x of the domain and find the value of f(x)

so

For x=-4 -----> f(-4)=3.2(-4)=-12.8

For x=-2 -----> f(-2)=3.2(-2)=-6.4

For x=0 -----> f(0)=3.2(0)=0

For x=2 -----> f(2)=3.2(2)=6.4

For x=4 -----> f(4)=3.2(-4)=12.8

therefore

The range is \{-12.8,-6.4,0,6.4,12.8\}

5 0
3 years ago
An art history professor assigns letter grades on a test according to the following scheme. A: Top 13%13% of scores B: Scores be
amm1812

Answer:

The numerical limits for a B grade is between 81 and 89.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 79.7, \sigma = 8.4

B: Scores below the top 13% and above the bottom 56%

Below the top 13%:

Below the 100-13 = 87th percentile. So below the value of X when Z has a pvalue of 0.87. So below X when Z = 1.127. So

Z = \frac{X - \mu}{\sigma}

1.127 = \frac{X - 79.7}{8.4}

X - 79.7 = 8.4*1.127

X = 89

Above the bottom 56:

Above the 56th percentile, so above the value of X when Z has a pvalue of 0.56. So above X when Z = 0.15. So

Z = \frac{X - \mu}{\sigma}

0.15 = \frac{X - 79.7}{8.4}

X - 79.7 = 8.4*0.15

X = 81

The numerical limits for a B grade is between 81 and 89.

3 0
3 years ago
Give the largest interval over which the general solution is defined. (Think about the implications of any singular points. Ente
Leto [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

   No singular point due to the exponent in the solution

    The interval is   -\infty

b

   NONE

Step-by-step explanation:

From the question we are told that

     \frac{dy}{dx} =  9y

The generally solution is mathematically represented as

         \frac{dy }{dx}  =  9y

=>       \frac{dy}{y}  =  9dx

integrating both sides  

         \int\limits  {\frac{ dy}{y} } \,  = \int\limits  {9} \, dx

  =>   lny = 9x + c

 =>   y =  e^{9x +c }

 =>    y =  e^{9x} e^{c}

Here e^c  =  C

=>     y = C  e^{9x}

From the above equation we see that the domain for x has no singular point the interval is

       -\infty

Also there is no transient term in the general solution obtained because as  x \to \infty there no case where y \to 0

7 0
3 years ago
PART A: At the bakery, the daily ratio of cookie sales to donut sales is 4 to 3. Cookies and donuts cost the same amount. If the
maksim [4K]
$<span>281.25

I got that from dividing 375.00 by 25% because 4 is 100% and 3 is 75%.</span>
3 0
4 years ago
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