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3 years ago

A sunflower turns its head toward sunlight. What triggers this behavior in a sunflower?

1 answer:

7 0

This is triggered by an activity known as heliotropism, or solar tracking. Special motor cells at the bases of the flowerbuds shrink or enlarge as they absorb water, which moves their faces toward the sun.

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What is the volume of a 1.2kg and displaced 1.0g/cm3

Zinaida [17]

Mass = 1.2 kg = 1200 grams.

Volume = mass/density = 1200 cm3.

Hope this helps!

4 0

3 years ago

A wire loop is suspended from a string that is attached to point P in the drawing. When released, the loop swings downward, from

Naddik [55]

Complete Question

The complete question iws shown on the first uploaded image

Answer:

$y \to z \to x$

$x \to z \to y$

Explanation:

Now looking at the diagram let take that the magnetic field is moving in the x-axis

Now the magnetic force is mathematically represented as

$F = I L$ x B

Note (The x is showing cross product )

Note the force(y-axis) is perpendicular to the field direction (x-axis)

Now when the loop is swinging forward

The motion of the loop is from y to z to to x to y

Now since the force is perpendicular to the motion(velocity) of the loop

Hence the force would be from z to y and back to z

and from lenze law the induce current opposes the force so the direction will be from y to z to x

Now when the loop is swinging backward

The motion of the induced current will now be x to z to y

5 0

3 years ago

Anika asks Eva to roll a basketball and then a bowling ball to her. Which requires more force to roll, and why?

Contact [7]

The bowling ball will require more force to roll because it is more massive.

3 0

3 years ago

Read 2 more answers

A muon has a rest mass energy of 105.7 MeV, and it decays into an electron and a massless particle. If all the lost mass is conv

sergeinik [125]

Answer:

The electron’s velocity is 0.9999 c m/s.

Explanation:

Given that,

Rest mass energy of muon = 105.7 MeV

We know the rest mass of electron = 0.511 Mev

We need to calculate the value of γ

Using formula of energy

$K_{rel}=(\gamma-1)mc^2$

$\dfrac{K_{rel}}{mc^2}=\gamma-1$

Put the value into the formula

$\gamma=\dfrac{105.7}{0.511}+1$

$\gamma=208$

We need to calculate the electron’s velocity

Using formula of velocity

$\gamma=\dfrac{1}{\sqrt{1-(\dfrac{v}{c})^2}}$

$\gamma^2=\dfrac{1}{1-\dfrac{v^2}{c^2}}$

$\gamma^2-\gamma^2\times\dfrac{v^2}{c^2}=1$

$v^2=\dfrac{1-\gamma^2}{-\gamma^2}\times c^2$

Put the value into the formula

$v^2=\dfrac{1-(208)^2}{-208^2}\times c^2$

$v=c\sqrt{\dfrac{1-(208)^2}{-208^2}}$

$v=0.9999 c\ m/s$

Hence, The electron’s velocity is 0.9999 c m/s.

6 0

3 years ago

Newton’s Laws of Motion are absolute in classical physics. One example that uses all three laws simultaneously is the firing of

Ksju [112]

Action and reaction are the rocket fuel going backwards and the rocket going forward. 3
f=ma 2
the rocket was at rest, 1, until there was a resultant external force 1 at which point 2 came in, with 3 alongside

4 0

3 years ago

Read 2 more answers