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Travka [436]
3 years ago
13

In an a.c generator, there are rings used. What are there names and how are they adapted to reversing current.​

Physics
2 answers:
lutik1710 [3]3 years ago
7 0
  • The slip rings are used in The AC generator .
  • The slip rings maintain constant contact with the same sides of the coil which help them reversing current .

AC generator works on The Faraday's Law

Digram attached .

djyliett [7]3 years ago
6 0

Answer:

In an a.c generator, slip rings are used.

Adaptation: <em>They</em><em> </em><em>are</em><em> </em><em>not</em><em> </em><em>directly</em><em> </em><em>connected</em><em> </em><em>directly</em><em> </em><em>to</em><em> </em><em>carbon</em><em> </em><em>brushes</em><em>,</em><em> </em><em>hence</em><em> </em><em>donot</em><em> </em><em>come</em><em> </em><em>into</em><em> </em><em>contact</em><em> </em><em>when</em><em> </em><em>the</em><em> </em><em>rectangular</em><em> </em><em>coil</em><em> </em><em>rotates</em><em>.</em>

Explanation:

.

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The electric field on the surface of an irregularly shaped conductor varies from 74.0 kN/C to 14.0 kN/C.
mrs_skeptik [129]

Answer:

(a). The local surface charge density at the point on the surface where the radius of curvature of the surface is greatest is 123.9 nC/m².

(b). The local surface charge density at the point on the surface where the radius of curvature of the surface is greatest is 654.9 nC/m².

Explanation:

Given that,

Electric field E_{1}=74.0\ kN/C

Electric field E_{2}=14.0\ kN/C

When the radius of curvature is greatest, the electric field at the surface will be smaller.

Where the radius of curvature is greatest

(a). We need to calculate the local surface charge density at the point on the surface

Using formula of charge density

\sigma=\epsilon_{0}E_{2}

Put the value into the formula

\sigma=8.85\times10^{-12}\times14\times10^{3}

\sigma=1.239\times10^{-7}\ C/m^2

\sigma=123.9\times10^{-9}\ C/m^2

\sigma=123.9\ nC/m^2

The local surface charge density at the point on the surface where the radius of curvature of the surface is greatest is 123.9 nC/m².

(b). We need to calculate the local surface charge density at the point on the surface where the radius of curvature of the surface is smallest

Using formula of charge density

\sigma=\epsilon_{0}E_{1}

Put the value into the formula

\sigma=8.85\times10^{-12}\times74\times10^{3}

\sigma=6.549\times10^{-7}\ C/m^2

\sigma=654.9\times10^{-9}\ C/m^2

\sigma=654.9\ nC/m^2

The local surface charge density at the point on the surface where the radius of curvature of the surface is greatest is 654.9 nC/m².

Hence, (a). The local surface charge density at the point on the surface where the radius of curvature of the surface is greatest is 123.9 nC/m².

(b). The local surface charge density at the point on the surface where the radius of curvature of the surface is greatest is 654.9 nC/m².

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Answer:

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Explanation:

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Explanation:

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They are different in that, continental rift occurs within the continental plate that are on land.

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