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Nitella [24]
4 years ago
11

Answer the question please

Physics
2 answers:
Juli2301 [7.4K]4 years ago
8 0
The property that she is testing is what is known as the boiling point. This describes the temperature (given a pressure) that a liquid begins to transition into the gas phase. By monitoring the production of bubbles (gas), she is investigating the boiling points of the two liquids. Hope this helps!
Nataliya [291]4 years ago
3 0

Answer:

B. solubility I think lmk if its wrong

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S Problem Set<br> 2.) 6.4 x 109 nm to cm
anyanavicka [17]

Answer:

6.4\cdot 10^2 cm

Explanation:

First of all, let's convert from nanometres to metres, keeping in mind that

1 nm = 10^{-9} m

So we have:

6.4\cdot 10^9 nm \cdot 10^{-9} m/nm = 6.4 m

Now we can convert from metres to centimetres, keeping in mind that

1 m = 10^2 cm

So, we find:

6.4 m \cdot 10^2 cm/m = 6.4\cdot 10^2 cm

8 0
3 years ago
What is the difference between a meteorite and a asteroid?
Lady bird [3.3K]
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8 0
3 years ago
Read 2 more answers
A recent study found that electrons that have energies between 3.45 eV and 19.9 eV can cause breaks in a DNA molecule even thoug
vlada-n [284]

Answer:

The Minimum wavelength is  \lambda_{min}= 382.2nm

The Maximum wavelength is \lambda_{max}= 624.2nm

Explanation:

From the question we are told that  

              The energy range is  E_r = 3.25eV \ and  \ 19.9eV

   Considering E = 19.9eV

When a single photon is transferred to to an electron the energy obtained can be calculated as follows

              E = 19.9eV = 19.9 *1.6 *10^{-19}J

This energy is mathematically represented as

                    E = \frac{hc}{\lambda_{max}}

Here h is the Planck's constant with value of  h= 6.625*10^{-34}J\cdot s

        c is the speed of light with value of  c = 3*10^8 m/s

Substituting values and making \lambda the subject of the formula

                       \lambda_{max} = \frac{hc}{E}

                         = \frac{6.625*10^{-34} * 3.0*10^{8}}{19.9*1.6*10^{-19}}

                         \lambda_{max}= 624.2nm

  Considering E = 3.25eV

When a single photon is transferred to to an electron the energy obtained can be calculated as follows

              E = 19.9eV = 3.25 *1.6 *10^{-19}J

This energy is mathematically represented as

                    E = \frac{hc}{\lambda_{min}}

Substituting values and making \lambda the subject of the formula

                       \lambda_{min} = \frac{hc}{E}

                           = \frac{6.625*10^{-34} * 3.0*10^{8}}{3.25*1.6*10^{-19}}

                           \lambda_{min}= 382.2nm

3 0
3 years ago
Calculate the kinetic energy of a car that travels at a speed of 20 m/s and has a mass of 1200 Kg
Sophie [7]
1200 times 20 times 9.6=24000j
3 0
3 years ago
7) A6 kg ball is thrown at 12 m/s. What is the momentum of the ball before it strikes a pin?
Rainbow [258]
Hope it helps and it’s right

6 0
3 years ago
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