Answer:
Step-by-step explanation:
2(2x +4) - 2x = x + 18
4x +8 -2x = x +18
2x -x = 18-8
X = 10
Put the value of x in both side
Left side *+*+*+*+*+
2 ( 2*10+4)-2*10
48-20 = 28
Right side +*+*+*+*+*
X + 18
10+ 18 = 28
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Answer:
$600
Step-by-step explanation:
Let "x" represent their total budget for the film.
Amount spent on costumes = $330
Percent spent on costumes = 55%
Therefore:
55% of x = $330
55/100 × x = 330
55x/100 = 330
Cross multiply
55x = 100 × 330
55x = 33,000
Divide both sides by 55
x = 33,000/55
x = 600
Total budget = x = $600
Answer:
i- ;-;
Step-by-step explanation:
Answer:
18x + 13y = 60
6x + 2y = 6 ---> 6x = -2y +6 ---> 18x = -6y+18
Substitution
(-6y +18)+13y =60
-18 -18
--------------------------
7y = 42 so y=6
Then, 6x + 2(6) =6, which you will get x = -1
(-1, 6)
Answer:
Let's define the variables:
A = price of one adult ticket.
S = price of one student ticket.
We know that:
"On the first day of ticket sales the school sold 1 adult ticket and 6 student tickets for a total of $69."
1*A + 6*S = $69
"The school took in $150 on the second day by selling 7 adult tickets and student tickets"
7*A + 7*S = $150
Then we have a system of equations:
A + 6*S = $69
7*A + 7*S = $150.
To solve this, we should start by isolating one variable in one of the equations, let's isolate A in the first equation:
A = $69 - 6*S
Now let's replace this in the other equation:
7*($69 - 6*S) + 7*S = $150
Now we can solve this for S.
$483 - 42*S + 7*S = $150
$483 - 35*S = $150
$483 - $150 = 35*S
$333 = 35*S
$333/35 = S
$9.51 = S
That we could round to $9.50
That is the price of one student ticket.
