Question

4a to the fourth power -2b to the second power +40 when a =2 and b =7

Answer 1

4a to the fourth power -2b to the second power +40 means that
4a^4-2b^2+40 when a=2 and b=7, so
4a^4-2b^2+40
Substitute a with 2 and b with 7
4(2)^4-2(7)^2+40
=4(16)-2(49)+40
=64-98+40
=-34+40
=6. As a result, the correct answer is 6. Hope it help!

Answer 2

Hi!

Let's set up the equation.

$4^{a} - 2^{b} + 40$

Put in the values...

$4^{2} - 2^{7} + 40$

Now solve using PEMDAS

Exponents
$16 - 128 + 40$

Subtract
$-112 + 40$

Add
$-72$

The answer is -72

Hope this helps! :)