Answer:
[300.202 , 329.798]
Step-by-step explanation:
The 95% confidence interval is given by the interval
![\large [\bar x-t^*\frac{s}{\sqrt n}, \bar x+t^*\frac{s}{\sqrt n}]](https://tex.z-dn.net/?f=%5Clarge%20%5B%5Cbar%20x-t%5E%2A%5Cfrac%7Bs%7D%7B%5Csqrt%20n%7D%2C%20%5Cbar%20x%2Bt%5E%2A%5Cfrac%7Bs%7D%7B%5Csqrt%20n%7D%5D)
where
<em>is the sample mean </em>
<em>s is the sample standard deviation </em>
<em>n is the sample size (n = 7) </em>
is the 0.05 (5%) upper critical value for the Student's t-distribution with 6 degrees of freedom (sample size -1), which is <em>an approximation to the Normal distribution for small samples (n<30).</em>
Either by using a table or the computer, we find

and our 95% confidence interval is
![\large [315-2.447*\frac{16}{\sqrt{7}}, 315+2.447*\frac{16}{\sqrt{7}}]=\boxed{[300.202,329.798]}](https://tex.z-dn.net/?f=%5Clarge%20%5B315-2.447%2A%5Cfrac%7B16%7D%7B%5Csqrt%7B7%7D%7D%2C%20315%2B2.447%2A%5Cfrac%7B16%7D%7B%5Csqrt%7B7%7D%7D%5D%3D%5Cboxed%7B%5B300.202%2C329.798%5D%7D)
Answer:
52.74% probability that a randomly selected airfare between these two cities will be between $325 and $425
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

What is the probability that a randomly selected airfare between these two cities will be between $325 and $425?
This is the pvalue of Z when X = 425 subtracted by the pvalue of Z when X = 325. So
X = 425



has a pvalue of 0.7088
X = 325



has a pvalue of 0.1814
0.7088 - 0.1814 = 0.5274
52.74% probability that a randomly selected airfare between these two cities will be between $325 and $425
8z = 64
divide both sides with 8
8z ÷8 = 64÷8
therefore,
z = 8.
Answer:
D
Step-by-step explanation: