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murzikaleks [220]
3 years ago
6

Please answer quickly thanks :)))

Mathematics
2 answers:
soldi70 [24.7K]3 years ago
4 0
From least to greatest: |6.99|,|-7.09|,|7.15|,|-7.18|,|-7.21|. This is becauase every value will be positive because of the absolute value
fomenos3 years ago
4 0
6.99 7.09 7.15 -7.18 and 7.21
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I need help on number 3
TiliK225 [7]
Divide 17.5 by 0.07
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5 0
3 years ago
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EM Company produces two types of laptop computer bags. The regular version requires $32 in capital and 4 hours of labor and sell
expeople1 [14]

Answer:

Step-by-step explanation:

Given that EM company produces two types of laptop computer bags.

Let regular version produced be R and deluxe version be D

Total capital required

= 32R+38D\leq 2100

Total labor hours required

=4R+6D\leq 280

Sales revenue = 46R+55D

Solving the two constraints we have

10D \leq 140

D can be atmost 14 and hence R can be 49

Otherwise if D is made 0, R = 65 maximum

If R is made 0, D maximum is 46

Thus corner points are (65,0) (0.,46) or (49,14)

Sales revenue for (65,0) = 2990

(0,46) is 2530

(49,14) is 3024

Maximum when R =14 and D is 49

5 0
3 years ago
What are the missing terms 64, -32, 16, -8, ___, ___?
Daniel [21]

Divide by -2 for all of the numbers

64/-32=-2

-32/ 2= -16

-16/2= -8

-8/-2= 4

4/-2= -2

Answer : 4 ,-2

5 0
3 years ago
Read 2 more answers
Use a matrix equation to solve the system of linear equations. left brace Start 2 By 1 Matrix 1st Row 1st Column 2nd Row 1st Col
natali 33 [55]

Answer:

\left[\begin{array}{ccc}3&-1&\\-1&1/2\\\end{array}\right]

Step-by-step explanation:

The matrix system for the linear equations: x + 2y = 8, 2x + 6y = 9

\left[\begin{array}{ccc}1&2&\\2&6\\\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}8\\9\end{array}\right]

To get the coefficient of x and y, the inverse of the first matrix (let the first matrix be A) must be known.

A^{-1} = (1 / determinant of A) x Adjoint of A

the determinant of A = (1 x 6) - (2 x 2) = 6 - 4 = 2

Adjoint of A = \left[\begin{array}{ccc}6&-2&\\-2&1\\\end{array}\right]

A^{-1}= \frac{1}{2} \left[\begin{array}{ccc}6&-2\\-2&1\end{array}\right] = \left[\begin{array}{ccc}3&-1&\\-1&1/2\\\end{array}\right]

4 0
2 years ago
17/20
Lena [83]

Answer:

2.39 cm

Step-by-step explanation:

6 0
2 years ago
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