a street light is mounted at the top of a 15 ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 5 ft/s along
a straight path. How fast is the tip of his shadow moving when he is 40 ft from the pole
1 answer:
You might be interested in
Answer:
y = -2x - 2
Step-by-step explanation:
From the graph attached,
If the line 'l' passes through two points A(0, -1) and B(4, 1).
Rule for the rotation of any point (x, y), 90° clockwise about the origin is,
(x, y) → (y, -x)
By this rule,
A(0, -1) → A'(-1, 0)
B(4, 1) → B'(1, -4)
Let the equation of the line A'B' is,
y - y' = m(x - x')
where m = slope of the line A'B'
And (x', y') is a point lying on the line.
Slope of the line passing through A' and B' will be,
m =
m =
m = -2
Therefore, equation of the line passing through (-1, 0) and slope = -2,
y - 0 = (-2)(x + 1)
y = -2x - 2
So the equation of the line after rotation of lie 'l' by 90° clockwise will be,
y = -2x - 2
Step-by-step explanation:
Below is an attachment containing the solution.
