The surface area is 47.1 sq in.
Step-by-step explanation:
Given,
The height (h) of the coin (cylinder shaped) = 5 inches
The radius (r) = 1.5 inches
To find the surface area of the coin.
We need to find the lateral surface area of the coin.
Formula
The surface area of the coin of radius r and height h is 2πrh.
Now,
Putting the value of h and r and π=3.14 we get,
Area = 2×3.14×1.5×5 sq inches
= 47.1 sq in
Hence, the surface area is 47.1 sq in.
Answer:
Step-by-step explanation:
a|c means that c=a*k k is some positive integer. We know that b|c so b| ak and (a,b)=1, so it must be b|k, i.e k=b*r, r is some positive integer number. Now we have that c=abr, so ab| c.
B) if x and x’ are both solution then we have that
mi | x-x’ for every i.
By a) we have that m1m2...mk| x-x’, so x and x’ are equal by mod od m1m2...mk.
2/3x + 4 = 7
-4 -4
4 cancels out.
2/3x = 3
x 3 x3
6/3 = 2x = 9
/2 /2
2 cancels out.
x = 9/2 = 4.5
Reduce the fraction with 2
Answer:
Container B has smaller surface area.
Step-by-step explanation:
Given:
Container A
Radius = 60/2 = 30 mm
Height = 4 x 60 = 240 mm
Container B
Length = 120
Width = 120
Height = 60
Computation:
Surface area of container A (Cylinder) = 2πr[h+r]
Surface area of container A (Cylinder) = 2[22/7][60][120+60]
Surface area of container A (Cylinder) = 67,885.70 mm² (Approx)
Surface area of container B (Cuboid) = 2[lb+bh+hl]
Surface area of container B (Cuboid) = 2[(14,400)+(7,200)+(7,200)]
Surface area of container B (Cuboid) = 57,600 mm²
Container B has smaller surface area.
