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3 years ago

7

What is the total number of unique triangles with side lengths of 4 centimeters. 5 centimeters, and 10 centimeters that can be d

rawn

1 answer:

alexandr1967 [171]3 years ago

3 0

Answer:

100

Step-by-step explanation:

10*5*4=200

200/2=100

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Please help my son asked me for this and I don't understand it.

Tasya [4]

Answer:

y = 2x + 3

Step-by-step explanation:

In the slope-intercept form of the equation of a line,

y = mx + b,

m = slope, and b = y-intercept.

Let's look at Adriana's equation and understand the parts:

y = 2x + 4

y = mx + b

m = slope = 2; b = y-intercept = 4

Now let's look at the description of Henry's equation.

He has the same slope as Adriana, so for Henry, m = 2 also.

His y-intercept is 1 less than Adriana's, so it is 1 less than 4. Henry's y-intercept is 3.

Now that we know that for Henry, m = 2, and b = 3, we can write his equation.

y = mx + b

y = 2x + 3

Answer: y = 2x + 3

7 0

2 years ago

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Complete the square to re-write the quadratic function in vertex form:<br> y = x2+ 10x - 2

Blababa [14]

Answer:

<h3> $\bold{y=(x+5)^2-27}$ </h3>

Step-by-step explanation:

$y = x^2+ 10x - 2\\\\y = x^2+ 2\cdot x\cdot5+5^2-5^2 - 2\\\\y=(x+5)^2-25-2\\\\y=(x+5)^2-27$

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4 years ago

Help me with this question I don’t really understand it:(

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Answer:

d

Step-by-step explanation:

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3 years ago

Find the area of this parallelogram.<br><br> 8.9 cm<br> 7.1 cm<br> 11.4 cm

defon

<h3>Answer: 80.94 square cm</h3>

==================================================

Work Shown:

Area of parallelogram = base*height

Area of parallelogram = 11.4*7.1

Area of parallelogram = 80.94 square cm

-------------

notes:

The base and height always form a 90 degree angle (as shown by the small square marker).
The side length of 8.9 cm is never used.
We can write "square cm" as "cm^2" or $\text{ cm}^2$

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3 years ago

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Find the volume of a trough 5 meters long whose ends are equilateral triangles, each of whose

yawa3891 [41]

Answer:

$V=5\sqrt{3}\ m^3$

Step-by-step explanation:

we know that

The volume of a trough is equal to

$V=BL$

where

B is the area of equilateral triangle

L is the length of a trough

step 1

Find the area of equilateral triangle B

The area of a equilateral triangle applying the law of sines is equal to

$B=\frac{1}{2} b^{2} sin(60\°)$

where

$b=2\ m$

$sin(60\°)=\frac{\sqrt{3}}{2}$

substitute

$B=\frac{1}{2}(2)^{2} (\frac{\sqrt{3}}{2})$

$B=\sqrt{3}\ m^{2}$

step 2

Find the volume of a trough

$V=BL$

we have

$B=\sqrt{3}\ m^{2}$

$L=5\ m$

substitute

$V=(\sqrt{3})(5)$

$V=5\sqrt{3}\ m^3$

3 0

4 years ago