Find the area of a sector with a central angle of 32° and a radius of 8.5 millimeters. Round to the nearest tenth.

1 answer:

5 0

360 degrees in a circle
32/360 of total area is sector area

area=pir^2
r=8.5
area=pi8.5^2
area=226.980022 mm^2
multiply it by 32/360
sector=20.17600195555556

round
sector=20.2

C is answer

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