First we write the mathematical model in a generic way:
"The stopping distance of an automobile is directly proportional to the square of its speed v"
d = kv ^ 2
Where,
k: proportionality constant.
We now look for the value of K:
d = kv ^ 2
90 = k ((70) * (5280/3600)) ^ 2
k = 90 / ((70) * (5280/3600)) ^ 2
k = 0.008538539 s ^ 2 / feet
The equation will then be:
d = (0.008538539) * v ^ 2
For v = 71 miles per hour we have:
d = (0.008538539) * ((71) * (5280/3600)) ^ 2
d = 92.6 feet
Answer:
a mathematical model that gives the stopping distance in terms of its speed v is:
d = (0.008538539) * v ^ 2
The stopping distance if the brakes are applied when the car is traveling at 71 miles per hour is:
d = 92.6 feet
Answer:−6y+9.6z−3
Step-by-step explanation:−(6y−9.6z+3)
−6y+9.6z−3
X would equal 2.7 //////////////
Answer:
31,536,000
Step-by-step explanation:
There are 3600 seconds in an hour and 24 hours in a day, so ...
(3600 s/h)(24 h/da) = 86400 s/da
Then in 365 days, there are ...
(365 da)(86400 s/da) = 31,536,000 s
_____
No rounding is needed.
