If A=106 then M1=? <br> please answerrr

Is x^2+3x+8 a monomial, binomial, or trinomial

torisob [31]

Answer:

A trinomial

Step-by-step explanation:

Since there are three terms, x^2, 3x, and 8, it is a trinomial

6 0

3 years ago

Plz help me with this question

irga5000 [103]

Answer:

122

Step-by-step explanation:

$x^6+y^2$

Plug in 1 for x and 11 for y

$=1^6+11^2$

1 to the power of any number will always equal 1

$=1+11^2\\=1+121\\=122$

I hope this helps!

7 0

2 years ago

A protein mix claims to contain a bonus of 20% more mix than the usual size container. If the bonus size contains 18 ounces of m

agasfer [191]

Answer:

The usual size of the container is 15 ounces.

Step-by-step explanation:

Consider the provided information.

A protein mix claims to contain a bonus of 20% more mix than the usual size container.

Let the usual size of the container was x ounces.

They increase 20% of usual size and the bonus size is 18 ounces.

Therefore, the new size should be:

$x+20\%x=18$

$x(1+0.20)=18$ (∴20%= $\frac{20}{100}$ =0.20)

$x(1.20)=18$

$x=\frac{18}{1.20}$

$x=15$

Hence, the usual size of the container is 15 ounces.

3 0

3 years ago

Use the distributive property to remove the parentheses. (y-3)10

vlada-n [284]

Answer:

10y-30

Step-by-step explanation:

10*1y=10y

-3*10=-30

10y-30

3 0

2 years ago

Let v⃗ 1=⎡⎣⎢033⎤⎦⎥,v⃗ 2=⎡⎣⎢1−10⎤⎦⎥,v⃗ 3=⎡⎣⎢30−3⎤⎦⎥ be eigenvectors of the matrix A which correspond to the eigenvalues λ1=−1, λ2

kaheart [24]

Answer:

- x as a linear combination :

x = -1 v1+ 0 v2+ 1 v3.

- Transpose Ax = (12, -6, -6)

Step-by-step explanation:

Given v1 = (0 3 3),v2 = (1 −1 0), v3 = (3 0 −3) be eigenvectors of the matrix A which correspond to the eigenvalues λ1 = −1, λ2 = 0, and λ3 = 1, respectively, and let x = (−2 −4 0). Express x as a linear combination of v1, v2, and v3, and find Ax .

To write x as a linear combination of v1, v2, and v3

x = -1 v1+ 0 v2+ 1 v3.

To find Ax

Write A = (0 ......3 ......3 )

...................(1 ......-1 ......0)

...................(3 ......0......-3)

Since transpose x = (-2, 4, 0)

Ax =......... (0 ......3......3 )(-2)

...................(1 ......-1 ......0)(4)

...................(3 ......0......-3)(0)

= (0×-2 + 3×4 + 3×0)

...(1×-2 + -1×4 + 0×0)

.. (3×-2 + 0×4 + -3×0)

As = (12)

....(-6)

Transpose Ax = (12, -6, -6)

7 0

3 years ago

If A=106 then M1=? please answerrr