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Zepler [3.9K]
3 years ago
15

Gina visits her local farm stand to buy apples and oranges to make a fruit salad. She has​ $10.00 to spend. If she buys only ora

nges and oranges are $0.34 how much oranges can she buy
Mathematics
1 answer:
icang [17]3 years ago
3 0

Answer:

29 oranges rounding up but the exact answer is 29.41176

Step-by-step explanation:

It would be 29.41176 if you want the answer to be exact. All you're doing is dividing 10.00 ÷ 0.34 and getting 29 oranges :)

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Which of the following values is a solution of 12.6 = 3x?
Leona [35]

Answer:

X= 4.2

Step-by-step explanation:

To get x by itself all you have to do is divide both sides by 3 and 12.6 divided by 3 is 4.2

3 0
3 years ago
Read 2 more answers
4) Please help with question. MARKING BRAINLIEST AND 10 POINTS!!!!!!!!!!!!!! :D
baherus [9]
Since we can use direct substitution, we can just plug in x=0 into the equation.

x^{2} -1

=0^{2}-1

=-1

Thus, your answer is the first choice.

Have an awesome day! :)
5 0
3 years ago
Point B lies on AC between
Alecsey [184]

Answer:

A___B___C

AC = AB+ BC

3x +12 = ( 14) + (3-2x)

3x + 12 = – 2x + 17

3x + 2x = 17 - 12

5x = 5

x=5/5

x = 1

AC = 3x + 12 = 3(1) + 12 = 3 + 12= 15

I hope I helped you^_^

5 0
3 years ago
2x^2-8x factor<br> the folowing polynomials
raketka [301]
2(x-4)x is your answer
5 0
2 years ago
The output of a chemical process is continually monitored to ensure that the concentration remains within acceptable limits. Whe
marissa [1.9K]

Answer:

a)  0.31 = 31%

b) 0.03 = 3%

c) 0.36 = 36%

d) 2 times

Step-by-step explanation:

If F_X(x) is the cumulative distribution function of the random variable X, then by definition the probability P of the random variable is given by

P(X \leq x) = F_X(x)

If additionally the random variable is discrete (only has non-negative integers as outcomes as is the case in this problem) then

P(X=a)=F_X(a)-\lim_{x \to a^-}F_X(x)

a)

We are looking for P(X<2)

P(X < 2) = P(X\leq 2)-P(X=2)=F_X(2)-\lim_{x \to 2^-}F_X(x)=0.84-0.53=0.31

b)

In this case we want P(X>3)

P(X >3) = 1-P(X\leq 3)=1-F_X(3)=1-0.97=0.03

c)

Now, we are interested in P(X=1)

P(X =1) =F_X(1)-\lim_{x \to 1^-}F_X(x)=0.53-0.17=0.36

d)

The expected number of times that the process is recalibrated during the week is the expected value of the probability distribution:

P(X=1)+2P(X=2)+...+nP(X=n)+...

But it is easy to see that P(X=n) = 0 if n is an integer >4

So, the expected value is

P(X=1)+2P(X=2)+3P(X=3)+4P(X=4)

We already have P(X=1) and P(X=2). Let's compute the rest

P(X =3) =F_X(3)-\lim_{x \to 3^-}F_X(x)=0.97-0.84=0.13

P(X =4) =F_X(4)-\lim_{x \to 4^-}F_X(x)=1-0.97=0.03

and the expected value is

0.36 + 2*0.53+3*0.13+4*0.03= 1.93 = 2 times rounding to the nearest integer.

8 0
4 years ago
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