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harina [27]
3 years ago
5

Find the payment necessary to amortize a 6.3% loan of 7500 compounded semiannually, with 6 semiannual payments. Find the payment

necessary to amortize the loan and the total payments and the total amount of interest paid based on calculated semiannual payments.
Mathematics
1 answer:
Lorico [155]3 years ago
6 0

Answer:

Semiannual payment = $ 1391.37

Total payment = $ 8348.22

Interest paid =  $ 848.22

Step-by-step explanation:

Since, the semiannual payment formula of a loan,

P=\frac{PV(\frac{r}{2})}{1-(1+\frac{r}{2})^{-n}}

Where,

PV = present value of the loan,

n = number of semiannual payments,

r = annual rate,

Here, PV = 7500, r = 6.3% =0.063, n = 6,

By substituting the value,

The semiannual payment would be,

P=\frac{7500(\frac{0.063}{2})}{1-(1+\frac{0.063}{2})^{-6}}

\approx \$ 1391.37

Also, total payment = semiannual payment × total semiannual periods

= 1391.37 × 6

= $ 8348.22,

Also, the interest paid = total payment - present value

= 8348.22 - 7500

= $ 848.22

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Step-by-step explanation:

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(b) P(X\geq5) = 1-P(X\leq4) = 1 - (0.873 + (25C3)(0.05^3)(0.95^{22}) + (25C4)(0.05^4)(0.95^{21})) = 1 - (0.873 + 0.12) = 0.007

(c) P(1\leqX\leq4) = (25C1)(0.05^1)(0.95^{24}) + (25C2)(0.05^2)(0.95^{23}) + (25C3)(0.05^3)(0.95^{22}) + (25C4)(0.05^4)(0.95^{21}) = 0.715

(d) P(X=0) = (25C0)(0.05^0)(0.95^{25}) = 0.277  

(e) E(X) = np = (25)(0.05) = 1.25 and Sd(X) = \sqrt{Var(X)} = \sqrt{np(1-p)} = 1.09

8 0
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Step-by-step explanation:

Since we believe it  

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