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3 years ago

This circuit diagram lacks a basic feature of a circuit.

Physics

2 answers:

Oduvanchick [21]3 years ago

8 0

<h2>Answer:</h2>

The correct answer is the option D. Hence a device that uses the energy is missing in the circuit.

<h3>Explanation:</h3>

Normally the circuit is something/picture which graphically represents the electrical circuit. It is generally a closed pathway containing different devices.

A general electric circuit includes:

A voltage source: An energy source Like battery.
A switch: A button which is used to on/off the circuit. It actually completes the circuit when it is on and incomplete the circuit when it is off.
A device which uses current: There is a bulb or a device which indicates the completeness of circuit. For example when a bulb is on in a circuit it shows that the current is flowing in circuit.

So in above circuit there are first two components missing third one which as a indicator or device through which current will pass.

Salsk061 [2.6K]3 years ago

4 0

The basic feature that is missing from the circuit is D) a device that uses energy

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Ostrovityanka [42]

Answer:

$final-temperature = T_{f} = 252.51K$

Explanation:

we can solve this problem by using the first law of thermodynamics.

$\Delta U= Q-W$

Q= heat added

U= internal energy

W= work done by system

$E_{final}= E_{initial}$

$C_{v}(N_{2})=1.04\frac{KJ}{Kg K}$

$C_{v}(He)=5.193\frac{KJ}{Kg K}$

now

From equation 1

$T_{f}=\frac{C_{v}( N_{2}) T_{N_{2} } C_{v} (He) T_{He}}{C_{v} (N_{2}) C_{v}(He)}$

$T_{f} = \frac{315\times1.04+5.193\times240}{1.04+5.193}$

$T_{f} = 252.51K$

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4 years ago

Sum of number of protons and neutrons in the nucleus

Alina [70]

That's the "Atomic Mass" of the atom.

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4 years ago

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nika2105 [10]

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3 years ago

A ball attached to a string is whirled around in a horizontal circle having a radius R. If the radius of the circle is changed t

ivanzaharov [21]

Answer:

twice the original speed

Explanation:

the centripetal force is the force of an object moving in a circle of turning and it is given by the expression

$F=\frac{mv^{2} }{r}$

where f = force of the object

m = mass

v = velocity

r = radius of the circle

first we need to know what the orignal speed will be then we can tell what will happen if the radius of the circle is changed to 4R.

from the expression for the centripetal force, we need to make the velocity subject of the formula

$F = \frac{mv^{2} }{r} \\cross multiplying\\Fr =mv^{2} \\dividing both sides by m\\\frac{Fr}{m}=v^{2} \\taking the square root of both sides\\v=\sqrt{\frac{Fr}{m} }$

now, if the radius is changed to 4R

in the expression for v above i will need to just insert 4R in place of r

$v=\sqrt{\frac{4rF}{m} } \\$

the square root of 4 is 2,

therefore

$v=2\sqrt{\frac{rF}{m} }$

we can see that this is just twice of what the original speed was.

8 0

4 years ago

Three moles of an ideal gas undergo a reversible isothermal compression at 22.0°C. During this compression, 1700 J of work is do

densk [106]

Answer:

change in entropy is - 5.7627 J/K

Explanation:

Given data

temperature = 22.0°C = 22 + 273 = 295 K

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to find out

change in entropy

solution

we know that change in entropy = Q /T ......1

from 1st law of thermodynamic we know

Q =W for change in internal energy = 0

Q = -1700 J

so from equation 1

change in entropy = - 1700 / 295

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so change in entropy is - 5.7627 J/K

5 0

3 years ago