How many electrons must be added to an object to give it an overall net charge of -3.0 x 10^-7 C? The charge of an electron is -

Question

3 years ago

13

1.602 x 10^-19 C.
1.9 x 10^12 electrons
3.1 x 10^13 electrons
2.0 x 10^10 electrons
1.4 x 10^14 electrons

1 answer:

katovenus [111] · Answer 1 · 2022-07-16T14:40:22+03:00

The number of electrons is $1.9\cdot 10^{12}$

Explanation:

The total net charge on a negatively-charged object is given by

$Q=Ne$

where:

N is the number of excess electrons

$e$ is the charge of a single electron

In this problem, we have

$Q=-3.0\cdot 10^{-7}C$ is the overall charge of the object

$e=-1.602\cdot 10^{-19}C$ is the charge of one electron

Solving the equation for N, we find:

$N=\frac{Q}{e}=\frac{-3.0\cdot 10^{-7}}{-1.602\cdot 10^{-19}}=1.9\cdot 10^{12}$

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