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ivolga24 [154]
3 years ago
12

Three moles of an ideal gas undergo a reversible isothermal compression at 22.0°C. During this compression, 1700 J of work is do

ne on the gas. What is the change in entropy of the gas? (J/K)
Physics
1 answer:
densk [106]3 years ago
5 0

Answer:

change in entropy is - 5.7627 J/K

Explanation:

Given data

temperature = 22.0°C = 22 + 273 = 295 K

work is done = 1700 J

to find out

change in entropy

solution

we know that change in entropy = Q /T  ......1

from 1st law of thermodynamic we know

Q =W for change in internal energy = 0

Q = -1700 J

so from equation 1

change in entropy = - 1700 / 295

change in entropy = - 5.7627

so change in entropy is - 5.7627 J/K

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thus an evolutionary process.Aerial roots are often thick and spread around the parent tree. The Banyan tree can have several aerial roots as it gets older.

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4 years ago
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4 years ago
What is occurring in the umbra?
matrenka [14]

Answer:

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Explanation:

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3 0
3 years ago
An electron is released from rest at a distance of 0.570 m from a large insulating sheet of charge that has uniform surface char
Lelu [443]

Explanation:

Formula to calculate the electric field of the sheet is as follows.

          E = \frac{\sigma}{2 \epsilon_{o}}

And, expression for magnitude of force exerted on the electron is as follows.

            F = Eq

So, work done by the force on electron is as follows.

           W = Fs

where,     s = distance of electron from its initial position

                  = (0.570 - 0.06) m

                  = 0.51 m

First, we will calculate the electric field as follows.

              E = \frac{\sigma}{2 \epsilon_{o}}

                 = \frac{4.60 \times 10^{-12}C/m^{2}}{2 \times 8.854 \times 10^{-12}C^{2}/N m^{2}}

                 = 0.259 N/C

Now, force will be calculated as follows.

                 F = Eq

                    = 0.259 N/C \times 1.6 \times 10^{-19} C

                    = 0.415 \times 10^{-19} N

Now, work done will be as follows.

                    W = Fs

                        = 0.415 \times 10^{-19} N \times 0.51 m

                        = 2.12 \times 10^{-20} J

Thus, we can conclude that work done on the electron by the electric field of the sheet is 2.12 \times 10^{-20} J.

3 0
4 years ago
Read 2 more answers
Suppose a truck has a momentum of 40,120 kg • and a mass of 1,180 kg. what is the truck’s velocity?
klasskru [66]
The momentum of an object is the product between the mass m of the object and its velocity:
p=mv
The truck in our problem has momentum equal to
p=40120 kg m/s 
and a mass of
m=1180 kg
so, if we re-arrange the previous formula, we can use these data to find the velocity of the truck:
v= \frac{p}{m}= \frac{40120 kg m/s}{1180 kg}=34 m/s
5 0
3 years ago
Read 2 more answers
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