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sergey [27]
3 years ago
15

Given that ƒ(x) = 4x + 5 and g(x) = x2 – 2x – 2, find (ƒ + g)(x). Question 11 options: A) (ƒ + g)(x) = x2 + 6x + 3 B) (ƒ + g)(x)

= –x2 + 6x + 7 C) (ƒ + g)(x) = x2 + 2x + 3 D) (ƒ + g)(x) = –x2 + 2x – 7
Mathematics
1 answer:
baherus [9]3 years ago
4 0

Answer: C

Step-by-step explanation:

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What is the equation of the line that passes through the point (3,-3) and has a slope of 0?
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here

(y-y1) =m(x-x1)

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Need help for question 8 and 9. I need the equation that’s passes through the points!
dsp73

Answer:

Step-by-step explanation:

Question 8

Let the equation of a line passing through two points (x_1,y_1) and (x_2,y_2) is given by,

y = mx + b

Here, m = slope and y-intercept = b

Since, m = \frac{y_2-y_1}{x_2-x_1}

For two points (1, 4) and (5, 8),

m = \frac{8-4}{5-1}

m = 1

Equation will be,

y = (1)x + b

y = x + b

Since, this line passes through (1, 4),

4 = 1 + b

b = 3

Therefore, equation of the line will be,

y = x + 3

Question 9

Let the equation is y = mx + b

m = \frac{y_2-y_1}{x_2-x_1}

For two points (2, 10) and (6, 4)

m = \frac{10-4}{2-6}

m = -\frac{3}{2}

By substituting the value of 'm' in the equation,

y = -\frac{3}{2}x+b

Since, this line passes through (2, 10)

10 = -\frac{3}{2}(2)+b

b = 10 + 2

b = 12

Therefore, equation of the line will be,

y=-\frac{3}{2}x+12

4 0
3 years ago
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