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In-s [12.5K]
3 years ago
11

On a coordinate plane, how are the locations of the points (-4 , 8) and (-4 , -8) related?

Mathematics
1 answer:
STALIN [3.7K]3 years ago
6 0

Answer:

A. reflection across the y-axiss

Step-by-step explanation:

Given:

The locations of the two points are (-4 , 8) and (-4 , -8).

To find:

The relation between two points.

From the given points (-4, 8) and (-4 , -8), it is clear that the y-coordinates are same but the sign of x-coordinates are opposite.

If a figure is reflected across the y-axis, then we change the sign of x-coordinate and the y-coordinates remain same, i.e.,

(x,y)→(-x,y)

For (-4,8)

(-4,8)→ (-4,-8)

So, it is reflection across the y-axis.

Therefore, the correct option is A.

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Step-by-step explanation:

Given

x - 2.6 = 1.8

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x = 4.4

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2 years ago
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Ella ran 6 times around her school building. Then she ran 4 miles home.
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Answer:

B.6x+4=7

Step-by-step explanation:

x represents how many miles is around her school building which she did 6 times, 4 miles is for the amount she ran home and 7 miles is the combination of the 6 times the miles around her school, 6x and the miles she ran home 4

making the equation 6x+4=7

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3 years ago
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A coin is tossed four times What is the probability of getting four heads? (1 mark) a) b) What is the probability of getting exa
BlackZzzverrR [31]
<h2>Answer:</h2>

1. A coin is tossed four times. What is the probability of getting four heads?

Each toss has a 1/2 chance of getting a head.

So the chance of getting all four heads can be calculated as :

1/2\times1/2\times1/2\times1/2=1/16

2. A coin is tossed four times. What is the probability of getting two heads?

Each toss can have 2 results, so 4 flips will have 2^{4} or 16 results.

Getting two heads means getting two tails also. So, we can get the number of times two heads come = \frac{4!}{2!2!} = 6

We can write the groups like - {HHTT,HTHT,HTTH,THHT,THTH,TTHH}

So, the required probability is : 6/16 or 3/8.

3. Not getting two heads means getting 3 tails and 1 head or all tails.

Probability of having all tails = 1/2\times1/2\times1/2\times1/2=1/16

Probability of one head(1st trial) and three tails = 1/16

Probability of one head (2nd trial) and three tails (the 1st, 3rd and 4th trials) = 1/16

Probability of one head (3rd trial) and three tails (the 1st, 2nd and 4th trials) = 1/16

Probability of one head (4th trial) and three tails (the 1st, 2nd and 3rd trials) = 1/16

So, the total probability showing only one or none head and at least three tails = 1/16+1/16+1/16+1/16+1/16=5/16

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3 years ago
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Answer:

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2 years ago
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Answer: Third option.

Step-by-step explanation:

You know that the drawbridge rises at a rate of 3\ \frac{2}{3} feet per minute. This means that the drawbridge rises  3\ \frac{2}{3} in a minutes.

Convert from mixed fraction to decimal number:

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Since the drawbridge rises to a height of 50 feet, you need to apply this procedure in order to find the time the drawbridge takes to completely rise:

time=\frac{(1\ min)(50\ ft)}{3.66\ ft}=13.6\ min or 13\ \frac{7}{11}\ min

7 0
3 years ago
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