Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 25235
For the alternative hypothesis,
µ > 25235
This is a right tailed test.
Since the population standard deviation is not given, the distribution is a student's t.
Since n = 100,
Degrees of freedom, df = n - 1 = 100 - 1 = 99
t = (x - µ)/(s/√n)
Where
x = sample mean = 27524
µ = population mean = 25235
s = samples standard deviation = 6000
t = (27524 - 25235)/(6000/√100) = 3.815
We would determine the p value using the t test calculator. It becomes
p = 0.000119
Since alpha, 0.05 > than the p value, 0.000119, then we would reject the null hypothesis. There is sufficient evidence to support the claim that student-loan debt is higher than $25,235 in her area.
Let x be the amount of nickels and y be the amount of quarters in a jar. Totally there are 87 coins, then x+y=87.
Since nickel is 5 cent coin and quarter is 25 cent coin, then 5x+25y=1255 ($12.55=1255 cents). Solve this system:x=87-y and 5(87-y)+25y=1255.
435-5y+25y=1255,
25y-5y=1255-435,
20y=820,
y=820÷20,
y=41,
x=87-41=46.
Answer: 46 nickels and 41 quarters.
Try using an app called Symbolab it helps a lot !
Answer:
<em>908360.67 lb-ft</em>
<em></em>
Step-by-step explanation:
height of tank= 6 ft
diameter of the tank = 4 ft
density of water p = 62.4 lbs/ft
A is the cross sectional area of the tank
A = 
where r = diameter/2 = 4/2 = 2 ft
A = 3.142 x 
= 12.568 ft^2
work done = force x distance through which force is moved
work = F x d
Force due to the water = pgAh
where g = acceleration due to gravity = 32.174 ft/s^2
Force = 62.4 x 32.174 x 12.568 x 6 = 151393.44 lb
work done = force x distance moved
work = 151393.44 x 6 = <em>908360.67 lb-ft</em>
Answer:
10%
Step-by-step explanation:
