Question

Assume that the number of pieces of junk mail per day that a person receives in their mail box follows the Poisson distribution and averages 4.3 pieces per day.
What is the probability that this person will not receive any junk mail tomorrow?
1) 0.5123
2) 0.5864
3) 0.6791
4) 0.7510

Answer 1

Answer:

0.01357

Step-by-step explanation:

The probability of an event X following a Poisson distribution happening 'n' times over an interval, given that the mean number of occurrences in the interval is λ, is determined by:

$P(X=n)=\frac{\lambda^n*e^{-\lambda}}{n!}$

If a person receives 4.3 pieces of junk mail per day (λ), the probability of receiving zero (n) junk mails in a day is:

$P(X=0)=\frac{4.3^0*e^{-4.3}}{0!}\\P(X=0) = 0.01357$

Therefore, the probability is 0.01357.

None of the answer choices provided are correct.