Answer:
c) Events A and B are independent events.
The outcomes of events A and B are dependent on each other.
P(A and B)=P(A)•P(B)
Step-by-step explanation:
Given:
Total number, n = 52
Each suit contains 13 cards: 2 to 10, a jack, a queen, a king, and an ace.
Since there are 4 suits, it means the number of each card is four.
P(A) = event of picking a king
P(B) = event of picking a 3
Therefore the probability of picking a king = ![P(A) = \frac{4}{52}](https://tex.z-dn.net/?f=%20P%28A%29%20%3D%20%5Cfrac%7B4%7D%7B52%7D)
Probability of picking a 3 = ![P(B) = \frac{4}{52}](https://tex.z-dn.net/?f=%20P%28B%29%20%3D%20%5Cfrac%7B4%7D%7B52%7D)
Since only a card is picked, the probability a king is picked after picking a 3 is 0.
i.e P(A|B) = 0 ≠ ![P(A) = \frac{4}{52}](https://tex.z-dn.net/?f=%20P%28A%29%20%3D%20%5Cfrac%7B4%7D%7B52%7D)
option A is wrong
The probability a 3 is picked after picking a king is 0.
i.e P(B | A) = 0 ≠ ![P(B) = \frac{4}{52}](https://tex.z-dn.net/?f=%20P%28B%29%20%3D%20%5Cfrac%7B4%7D%7B52%7D)
option B is wrong
Events A and B are independent events.
The outcomes of events A and B are dependent on each other.
P(A and B)=P(A)•P(B)
Option C is correct.