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Rus_ich [418]
3 years ago
13

Sending an identical message in an e-mail blast to all customers is an example of

Computers and Technology
1 answer:
disa [49]3 years ago
8 0

Answer:

Broadcast message

Explanation:

A broadcast message is an identical message sent to a lot of recipients. When it is an email, it can be sent in Carbon Copy (Cc) or a Blind Carbon Copy (Bcc) form.

With the<em> Carbon Copy</em>, every recipients will be notified about the other recipients. In most cases all the email usernames of the recipients will be sent to all the recipients individually.

With the <em>Blind Carbon Copy</em>, every individual sees the message as he/she received it alone. The individual is not notified about the other recipients.

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6 0
3 years ago
What is an IF statement used for?
kiruha [24]

The IF statement is a decision-making statement that guides a program to make decisions based on specified criteria. The IF statement executes one set of code if a specified condition is met (TRUE) or another set of code evaluates to FALSE.

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2 years ago
What four things does steering control involve?
Dafna1 [17]

Answer:

putting your hands one the wheel, putting the car in gear, putting your foot on the brakes when you need to, and watch for cars when you're driving. hope it helps

Explanation:

7 0
3 years ago
Input 10 integers and display the following:
LekaFEV [45]

Answer:

// code in C++

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables

   int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;

   int largest=INT_MIN;

   int smallest=INT_MAX;

   int n;

   cout<<"Enter 10 Integers:";

   // read 10 Integers

   for(int a=0;a<10;a++)

   {

       cin>>n;

       // find largest

       if(n>largest)

       largest=n;

       // find smallest

       if(n<smallest)

       smallest=n;

       // if input is even

       if(n%2==0)

       {  

           // sum of even

           sum_even+=n;

           // even count

           eve_count++;

       }

       else

       {

           // sum of odd    

          sum_odd+=n;

          // odd count

          odd_count++;

       }

   }

   

   // print sum of even

   cout<<"Sum of all even numbers is: "<<sum_even<<endl;

   // print sum of odd

   cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;

   // print largest

   cout<<"largest Integer is: "<<largest<<endl;

   // print smallest

   cout<<"smallest Integer is: "<<smallest<<endl;

   // print even count

   cout<<"count of even number is: "<<eve_count<<endl;

   // print odd cout

   cout<<"count of odd number is: "<<odd_count<<endl;

return 0;

}

Explanation:

Read an integer from user.If the input is greater that largest then update the  largest.If the input is smaller than smallest then update the smallest.Then check  if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.

Output:

Enter 10 Integers:1 3 4  2 10 11 12 44 5 20                                                                                

Sum of all even numbers is: 92                                                                                            

Sum of all odd numbers is: 20                                                                                              

largest Integer is: 44                                                                                                    

smallest Integer is: 1                                                                                                    

count of even number is: 6                                                                                                

count of odd number is: 4

3 0
3 years ago
In cell j6, enter a formula to determine the cost of gas if the customer chose that option as indicated in column i. if the cust
Alex73 [517]

Answer:

a t t i c

Explanation:

7 0
3 years ago
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