Answer:
B. Doesn’t get you to your location faster.
Explanation:
Following the car in front of you at a closer distance doesn’t get you to your location faster.
Answer:
Identify the location of the college stand in advance.
Explanation:
One way to save time and get to the colleges that you are most interested in at a college fair is to find out in advance the information about the fair, the colleges that are participating and from that pick the more interesting ones and identify the location of their stands. Like that when you arrive to the fair you can go directly to them and find them easily which will save you a lot of time as you won't be walking around the whole place to find them.
Answer: Analyze the organization's strategic plan
Explanation:
The initial step in the information system is to first analyze the strategic plan of the organization so that we can easily identify the main objective and challenge.
It is basically archived by enlisting the particular objective and function in the planning of information system in the organization.
All the remining option are involve in the remaining step of the information system planning not in the initial step.
Therefore, analyze the organization's strategic plan is correct as it is the first step of the information system planning.
Answer
First part:
The transmitted 8-bit sequence for ASCII character '&' with odd parity will be 00100110. Here leftmost bit is odd parity bit.
Second part:
The invalid bit sequence are option a. 01001000 and d. 11100111
Explanation:
Explanation for first part:
In odd parity, check bit of either 0 or 1 is added to the binary number as leftmost bit for making the number of 1s in binary number odd.
If there are even number of 1s present in the original number then 1 is added as leftmost bit to make total number of 1s odd.
If there are odd number of 1s present in the original number then 0 is added as leftmost bit to keep the total number of 1s odd.
Explanation for second part:
A valid odd parity bit sequence will always have odd number of 1s.
Since in option a and d, total number of 1s are 2 and 6 i.e. even number. Therefore they are invalid odd parity check bit sequences.
And since in option b and c, total number of 1s are 5 and 7 i.e. odd numbers respectively. Therefore they are valid odd parity check bit sequences.
Kaeya Should be the correct answer
